Answered: If 92.6 g of glucose (molar mass =…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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If 92.6 g of glucose (molar mass = 180.2 g/mol) is dissolved in 39.2 g of water, what is the vapor pressure of the solution (in mmHg)? (vapor pressure of pure water = 23.76 mmHg). Give your answer to three sig figs.

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$t h e m a s s o f w a t e r 39.2 g m m o l a r m a s s o f w a t e r 18 g m n u m b e r o f m o l e s w a t e r = \frac{39.2}{18} = 2.1777 m o l e s t h e m a s s o f g l u \cos e 92.6 g m m o l a r m a s s o f g l u \cos e 180.2 g m n u m b e r o f m o l e s g l u \cos e = \frac{92.6}{180.2} = 0.5138 m o l e s T h e t o t a l n u m b e r o f m o l e s i n t h e s o l u t i o n w i l l b e n t o t a l = n g l u \cos e + n w a t e r n t o t a l = 0.5138 m o l e s + 2.1777 m o l e s = 2.69165 m o l e s t h e m o l e f r a c t i o n o f g l u \cos e w i l l b e χ g l u \cos e = \frac{0.5138 m o l e s}{2.69165 m o l e s} = 0.19091$

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