l T-Mobile Wi-Fi ?[References)If 768 g of water is added to 38 g of a 4.9-mNaCl solution, what is the mass percent ofNaCl in the diluted solution?Mass percent=%3D

Answered: If 768 g of water is added to 38 g of a…

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter3: Chemical Reactions

Section: Chapter Questions

Problem 148QRT

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l T-Mobile Wi-Fi ?
[References)
If 768 g of water is added to 38 g of a 4.9-m
NaCl solution, what is the mass percent of
NaCl in the diluted solution?
Mass percent=
%3D

Expert Solution

Step 1: Mass of NaCl present

Molality of NaCl solution = 4.9 m

Mass of the solution = 38 grams

Mass of water added = 768 grams

Mass of NaCl present in the 4.9 m solution is :

Molality of a solution is the number of moles of solute present in 1 kg of solvent.

4.9 m NaCl solution is 4.9 moles of NaCl present in 1000 grams of water.

Mass of NaCl present is given by:

Molar mass of NaCl = 58.44 grams

$M o l a l i t y = \frac{N u m b e r o f m o l e s o f s o l u t e}{M a s s o f s o l v e n t i n k g} M o l a l i t y = \frac{M a s s o f N a C l}{M o l a r m a s s o f N a C l} \times \frac{1000}{M a s s i n g r a m s} M a s s o f N a C l = \frac{M o l a l i t y \times M o l a r m a s s o f N a C l \times M a s s o f s o l u t i o n i n g r a m s}{1000} M a s s o f N a C l = \frac{4.9 m \times 58.44 g r a m s \times 38 g r a m s}{1000} M a s s o f N a C l = 10.88 g r a m s$

So, 38 grams of 4.9 m NaCl solution will contain 10.88 grams of NaCl.

Now, 768 grams of water is added to 38 grams of 4.9 m NaCl solution.

So, now the total mass is 38 grams + 768 grams = 806 grams

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