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What is the mass percent of the following solution? 35 g of silver nitrate is mixed with 95 g of water. * O 73% silver nitrate O 27% silver nitrate O 2.7% silver nitrate O 37% silver nitrate

What is the mass percent of the following solution? 35 g of silver nitrate is mixed with 95 g of water. * O 73% silver nitrate O 27% silver nitrate O 2.7% silver nitrate O 37% silver nitrate

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Mass Percent Calculation #### Question: What is the mass percent of the following solution? 35 g of silver nitrate is mixed with 95 g of water. #### Options: - 73% silver nitrate - 27% silver nitrate - 2.7% silver nitrate - 37% silver nitrate #### Explanation: To calculate the mass percent of the silver nitrate in the solution, use the formula: \[ \text{Mass Percent} = \left( \frac{\text{Mass of Solute}}{\text{Mass of Solution}} \right) \times 100 \] Where: - The mass of the solute (silver nitrate) = 35 g - The mass of the solvent (water) = 95 g - The mass of the solution = Mass of solute + Mass of solvent = 35 g + 95 g = 130 g Thus, \[ \text{Mass Percent} = \left( \frac{35 \text{ g}}{130 \text{ g}} \right) \times 100 = 26.92\% \] Rounding off to the closest whole number gives approximately 27%. Hence, the correct answer is: - **27% silver nitrate**
Transcribed Image Text:### Mass Percent Calculation #### Question: What is the mass percent of the following solution? 35 g of silver nitrate is mixed with 95 g of water. #### Options: - 73% silver nitrate - 27% silver nitrate - 2.7% silver nitrate - 37% silver nitrate #### Explanation: To calculate the mass percent of the silver nitrate in the solution, use the formula: \[ \text{Mass Percent} = \left( \frac{\text{Mass of Solute}}{\text{Mass of Solution}} \right) \times 100 \] Where: - The mass of the solute (silver nitrate) = 35 g - The mass of the solvent (water) = 95 g - The mass of the solution = Mass of solute + Mass of solvent = 35 g + 95 g = 130 g Thus, \[ \text{Mass Percent} = \left( \frac{35 \text{ g}}{130 \text{ g}} \right) \times 100 = 26.92\% \] Rounding off to the closest whole number gives approximately 27%. Hence, the correct answer is: - **27% silver nitrate**
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