If 4.50 moles of NO₂ are allowed to react with excess H₂O according to the balanced equation: 3NO2 + H₂O 2HNO3 + NO, the amount (in moles) of HNO3 formed will be: O 3/2 x 4.50 O 2.00 O 2/3 x 4.50 O 4.50 OK
If 4.50 moles of NO₂ are allowed to react with excess H₂O according to the balanced equation: 3NO2 + H₂O 2HNO3 + NO, the amount (in moles) of HNO3 formed will be: O 3/2 x 4.50 O 2.00 O 2/3 x 4.50 O 4.50 OK
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.66PAE: 4.66 If 3.4 mol Al is mixed with 1.5 times as many moles of Fe2O3, what is the limiting reactant?...
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![If 4.50 moles of NO2 are allowed to react with
excess H₂O according to the balanced equation:
3NO2 + H₂O 2HNO3 + NO, the amount (in
moles) of HNO3 formed will be:
O 3/2 x 4.50
O 2.00
O 2/3 x 4.50
O 4.50
OK](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9dc8a740-4a7c-4dc9-b4cf-ccdbbbe87dbe%2F63072e31-9933-43e8-b0f1-754b1a43741a%2F1ju6xbr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:If 4.50 moles of NO2 are allowed to react with
excess H₂O according to the balanced equation:
3NO2 + H₂O 2HNO3 + NO, the amount (in
moles) of HNO3 formed will be:
O 3/2 x 4.50
O 2.00
O 2/3 x 4.50
O 4.50
OK
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