Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem Statement:**
If 23.5 mol of an ideal gas occupies 53.5 L at 97.00 °C, what is the pressure of the gas?
**Solution:**
To find the pressure, \( P \), use the Ideal Gas Law:
\[ PV = nRT \]
Where:
- \( P \) is the pressure in atmospheres (atm),
- \( V \) is the volume in liters (L),
- \( n \) is the number of moles (mol),
- \( R \) is the ideal gas constant, \( 0.0821 \, \text{L atm/mol K} \),
- \( T \) is the temperature in Kelvin (K).
**Calculation Steps:**
1. Convert the temperature from Celsius to Kelvin:
\[ T(K) = 97.00 + 273.15 = 370.15 \, \text{K} \]
2. Substitute the values into the Ideal Gas Law and solve for \( P \):
\[ P = \frac{nRT}{V} = \frac{(23.5 \, \text{mol})(0.0821 \, \text{L atm/mol K})(370.15 \, \text{K})}{53.5 \, \text{L}} \]
3. Calculate \( P \) using the values provided.
**Final Answer:**
\[ P = \boxed{ } \, \text{atm} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6797ee8f-35b0-45f9-be91-6b4961db7d8a%2F0dfb9b4d-b655-489d-ad3a-ca45aeb5252c%2Fgqk7eb_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
If 23.5 mol of an ideal gas occupies 53.5 L at 97.00 °C, what is the pressure of the gas?
**Solution:**
To find the pressure, \( P \), use the Ideal Gas Law:
\[ PV = nRT \]
Where:
- \( P \) is the pressure in atmospheres (atm),
- \( V \) is the volume in liters (L),
- \( n \) is the number of moles (mol),
- \( R \) is the ideal gas constant, \( 0.0821 \, \text{L atm/mol K} \),
- \( T \) is the temperature in Kelvin (K).
**Calculation Steps:**
1. Convert the temperature from Celsius to Kelvin:
\[ T(K) = 97.00 + 273.15 = 370.15 \, \text{K} \]
2. Substitute the values into the Ideal Gas Law and solve for \( P \):
\[ P = \frac{nRT}{V} = \frac{(23.5 \, \text{mol})(0.0821 \, \text{L atm/mol K})(370.15 \, \text{K})}{53.5 \, \text{L}} \]
3. Calculate \( P \) using the values provided.
**Final Answer:**
\[ P = \boxed{ } \, \text{atm} \]
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