If 23.5 mol of an ideal gas occupies 53.5 L at 97.00 °C, what is the pressure of the gas? P = atm

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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**Problem Statement:**

If 23.5 mol of an ideal gas occupies 53.5 L at 97.00 °C, what is the pressure of the gas?

**Solution:**

To find the pressure, \( P \), use the Ideal Gas Law:  
\[ PV = nRT \]

Where:  
- \( P \) is the pressure in atmospheres (atm),
- \( V \) is the volume in liters (L),
- \( n \) is the number of moles (mol),
- \( R \) is the ideal gas constant, \( 0.0821 \, \text{L atm/mol K} \),
- \( T \) is the temperature in Kelvin (K).

**Calculation Steps:**

1. Convert the temperature from Celsius to Kelvin:  
   \[ T(K) = 97.00 + 273.15 = 370.15 \, \text{K} \]

2. Substitute the values into the Ideal Gas Law and solve for \( P \):  
   \[ P = \frac{nRT}{V} = \frac{(23.5 \, \text{mol})(0.0821 \, \text{L atm/mol K})(370.15 \, \text{K})}{53.5 \, \text{L}} \]

3. Calculate \( P \) using the values provided.

**Final Answer:**
\[ P = \boxed{ } \, \text{atm} \]
Transcribed Image Text:**Problem Statement:** If 23.5 mol of an ideal gas occupies 53.5 L at 97.00 °C, what is the pressure of the gas? **Solution:** To find the pressure, \( P \), use the Ideal Gas Law: \[ PV = nRT \] Where: - \( P \) is the pressure in atmospheres (atm), - \( V \) is the volume in liters (L), - \( n \) is the number of moles (mol), - \( R \) is the ideal gas constant, \( 0.0821 \, \text{L atm/mol K} \), - \( T \) is the temperature in Kelvin (K). **Calculation Steps:** 1. Convert the temperature from Celsius to Kelvin: \[ T(K) = 97.00 + 273.15 = 370.15 \, \text{K} \] 2. Substitute the values into the Ideal Gas Law and solve for \( P \): \[ P = \frac{nRT}{V} = \frac{(23.5 \, \text{mol})(0.0821 \, \text{L atm/mol K})(370.15 \, \text{K})}{53.5 \, \text{L}} \] 3. Calculate \( P \) using the values provided. **Final Answer:** \[ P = \boxed{ } \, \text{atm} \]
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