If 0.3800g of KIIO3 (214.00 g/mol) was used to liberate free iodine which was then titrated with 205.80 mL sodium thiosulfate (158.11 g/mol) solution. Calculate the concentration of thiosulfate solution in mg/ml KIO3 + 5KI + 6 HCl ---- 3H20 +312+6KCI 2Na2S203 + 12 Na2S406 + 21
If 0.3800g of KIIO3 (214.00 g/mol) was used to liberate free iodine which was then titrated with 205.80 mL sodium thiosulfate (158.11 g/mol) solution. Calculate the concentration of thiosulfate solution in mg/ml KIO3 + 5KI + 6 HCl ---- 3H20 +312+6KCI 2Na2S203 + 12 Na2S406 + 21
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![If 0.3800g of KIO3 (214.00 g/mol) was used to
liberate free jodine which was then titrated with
205.80 mL sodium thiosulfate (158.11 g/mol)
solution. Calculate the concentration of
thiosulfate solution in mg/ml
KIO3 + 5KI + 6 HCl ---
3H20 +312+6KCI
2Na2S203 + 12
Na2S406 + 21](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F37f81852-4b48-4926-a562-6a6212e59aca%2Fcf21ae98-66dc-4601-8091-c9a8f2768147%2Ft8r5aoq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:If 0.3800g of KIO3 (214.00 g/mol) was used to
liberate free jodine which was then titrated with
205.80 mL sodium thiosulfate (158.11 g/mol)
solution. Calculate the concentration of
thiosulfate solution in mg/ml
KIO3 + 5KI + 6 HCl ---
3H20 +312+6KCI
2Na2S203 + 12
Na2S406 + 21
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