Identity of metal Mass of metal, (g) Copper 31.715 Trial 1 Mass of Styrofoam® cup and water, (g) 110.850 Mass of Styrofoam® cup, (g) 9.925 Trial 2 88.845 10.385 g Mass of water, (g) 100.925 78.46 Initial temperature of metal (Temperature of the boiling water) 90°C 98.5°C Initial temperature of water in cup, 22.5°C 22.5°C Final temperature of water and metal 25°C Specific heat of metal, (cal/g° C) Average specific heat of metal, (cal/g 33% 25°C 2.95% C) Calculations: ATwater Tf- Ti water °C ATmetal Tf-Ti metal ос = Qwater (1.00 cal/g°C) x ( _g H2O) x (°C) = cal Qmetal = - Qwater Cmatel Ometal/mmetal X ATmetal=- cal/[C g)x( °C)] = _cal/g°C

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Identity of metal
Mass of metal, (g)
Copper
31.715
Trial 1
Mass of Styrofoam® cup and water, (g)
110.850
Mass of Styrofoam® cup, (g)
9.925
Trial 2
88.845
10.385 g
Mass of water, (g)
100.925
78.46
Initial temperature of metal
(Temperature of the boiling water)
90°C
98.5°C
Initial temperature of water in cup,
22.5°C
22.5°C
Final temperature of water and metal
25°C
Specific heat of metal, (cal/g° C)
Average specific heat of metal, (cal/g
33%
25°C
2.95%
C)
Calculations:
ATwater Tf- Ti water
°C
ATmetal Tf-Ti metal
ос
=
Qwater (1.00 cal/g°C) x (
_g H2O) x (°C) =
cal
Qmetal = - Qwater
Cmatel
Ometal/mmetal X ATmetal=-
cal/[C
g)x(
°C)] =
_cal/g°C
Transcribed Image Text:Identity of metal Mass of metal, (g) Copper 31.715 Trial 1 Mass of Styrofoam® cup and water, (g) 110.850 Mass of Styrofoam® cup, (g) 9.925 Trial 2 88.845 10.385 g Mass of water, (g) 100.925 78.46 Initial temperature of metal (Temperature of the boiling water) 90°C 98.5°C Initial temperature of water in cup, 22.5°C 22.5°C Final temperature of water and metal 25°C Specific heat of metal, (cal/g° C) Average specific heat of metal, (cal/g 33% 25°C 2.95% C) Calculations: ATwater Tf- Ti water °C ATmetal Tf-Ti metal ос = Qwater (1.00 cal/g°C) x ( _g H2O) x (°C) = cal Qmetal = - Qwater Cmatel Ometal/mmetal X ATmetal=- cal/[C g)x( °C)] = _cal/g°C
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