pardF1QuestionEmilio wants to estimate the percentage of people who have a financial adviser. He surveys 350 individuals and finds that76 have a financial adviser.Identify the values needed to calculate a confidence interval at the 99% confidence level. Then find the confidence interval.Use the table of common z-scores above.• Round the final answer to three decimal places.Sorry, that's incorrect. Try again?p' =N||7.1.1 Central Limit Theorem for Means | Knewton==**F2OCT2580F3QF420.10 | 20.05 |70.025 | 20.01 20.0051.282 1.645 1.960 2.326 2.576OfConfidence Intervals for Population Proportion | Kne...ત્રF5~ /CFEEDBACKF6VIEW ANSWERF7Gtv ♫ Si diall ADIISUBMITF8F9

It is given that favourable cases, x = 76Sample size, n = 350Confidence level = 99%

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Crunch x + /courses/50327/quizzes/268370/take/questions/6536021 Mstructor via Chans possibi Make sure to take a screenshot of the last question you were working on and attach it to the email. D Question 2 33 When 390 junior college students were surveyed, 115 said that they have previously owned a motorcycle. Determine the point estimate to construct a 99% confidence interval of college students that have previously owned a motorcycle. Round your result to three decimal places: 29.487 Determine the critical value to construct a 99% confidence interval of college students that have previously owned a motorcycle. Round your result to two decimal places: 2.58 Calculate the Margin of Error for a 99% confidence interval of college students that have previously owned a motorcycle. Round your result to three decimal places: 4.114 Make sure to attach your work to this Quiz (see last question on quiz). Previous 10 Λ & Next▸ 3 pts
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n1=16 x‾1=124 s1=35 n2=12 x‾2=86 s2=31 Use this data to find the 98% confidence interval for the true difference between the population means. Assume that the population variances are not equal and that the two populations are normally distributed. Copy Data Step 2 of 3 : Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places. Step 3 of 3 : Please also find the high and low endpoints and round to four decimal points.
You measure 24 backpacks' weights, and find they have a mean weight of 34 ounces. Assume the population standard deviation is 10 ounces. Based on this, construct a 90% confidence interval for the true population mean backpack weight. Give your answers as decimals, to two places ounces
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Please do not give solution in image format thanku A dietitian wants to know the average time spent on breakfast in a primary school. The dietitian randomly samples 16 students and finds that the average is 15.8 minutes with a standard deviation of 2.31 minutes. Assume that the distribution of the time spent on the breakfast is normally distributed. The dietitian finds a 90% confidence interval for this sample is (14.788, 16.812). Select one or more: a. The margin of error is 1.012. b.The margin of error is 2.024 c. The margin of error is 0.950. d. We believe that the true mean time spent on breakfast in this primary school is between 14.788 and 16.812 minutes. e. If we take many other samples from this population, 90% of them will have a sample mean that is between 14.788 and 16.812. f. There is a 90% chance that the true mean is between 14.788 and 16.812 minutes.
Please solve for margin of error and sample proportion
Score: 30.8/100 7/16 answered Question 6 く> In a recent poll, 590 people were asked if they liked dogs, and 70% said they did. Find the Margin of Error for this poll, at the 90% confidence level. Give your answer to four decimal places if possible. Submit Question MacBook
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