Identify the structure of the oxygen-containing compound with m/z= 74 (M+ ), 56 and 31 from the ones below.
![ОН
HO
НО
A
В
D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4f496499-3588-4e79-98dd-6c561ba3f10b%2F2890796e-e760-4a6c-8994-ab1b2e73b9c0%2F3slr68c_processed.png&w=3840&q=75)
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The correct structure is B i.e. 1-butanol.
The molecular ion peak M+ is at m/z = 74 indicates that the molecular weight of the 1-butanol.
Primary alcohol shows an characteristic peak by loss of water molecule (M-18). Then second peak is due to the H2C=OH+ ion at m/z =31. This conforms the 1-butanol structure (B).
The 2-butanol (structure A) is not correct structure because it preferes the -cleavage either it lost methyl or the ethyl groups.
The structure C is not possible because the lost of -OH group it produce more stable tertiary cation which is the base peak .
The structure D is not possible because ether prefers the-cleavage either it lost methyl or the ethyl groups.
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