identify The research hypothesis H1 The null hypothesis HO The rejection region of the null hypothesis H1: H1 – H2 < 0 Họ: H1 - H2 > 0 1. H;: µ1 < H2 2. Ho: H1 2 H2 3. (-00, -tin-1)] 1. H;: H1 > H2 2. Ho: H1 < H2 3. (-00, tin-1] H1: H1 - H2 > 0 Ho: H1 - H2 < 0 H1: H1 - H2 > 0 Họ: H1 – H2 < 0 1. H;: H1 > H2 2. Ho: H1 < H2 3. [tin-1) , 0) 1. H;: H1 < H2 2. Ho: H1 2 H2 3. [t(n-1) , 0) H;: H1 – H2 < 0 Họ: 41 - H2 > 0

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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u1 = average of the grades of the students who were taught fractions with procedure A
µ2 = average of the grades of the students who were taught fractions with procedure B
A fourth grade teacher believes that Procedure A for teaching fractions is better than Procedure B.
identify
The research hypothesis H1
The null hypothesis H0
The rejection region of the null hypothesis
1. H1: 41 < H2
2. Hg: H1 > H2
3. (-00, -tin-1)]
H1: H1 – H2 < 0
Họ: H1 - H2 > 0
1. H;: H1 > H2
2. Ho: μι < μ2
3. (-00 , tin-1)]
H;: H1 - H2 > 0
Ho: 41 - H2 < 0
1. H1: H1 > H2
2. Họ: H1 < H2
3. [t(n-1) , 0)
H1: H1 – H2 > 0
Họ: 41 – H2 < 0
1. H;: H1 < H2
2. Ho: μι > μ2
3. [tin-1) , 0)
H;: H1 – H2 < 0
Ho: 41 - H2 > 0
Transcribed Image Text:u1 = average of the grades of the students who were taught fractions with procedure A µ2 = average of the grades of the students who were taught fractions with procedure B A fourth grade teacher believes that Procedure A for teaching fractions is better than Procedure B. identify The research hypothesis H1 The null hypothesis H0 The rejection region of the null hypothesis 1. H1: 41 < H2 2. Hg: H1 > H2 3. (-00, -tin-1)] H1: H1 – H2 < 0 Họ: H1 - H2 > 0 1. H;: H1 > H2 2. Ho: μι < μ2 3. (-00 , tin-1)] H;: H1 - H2 > 0 Ho: 41 - H2 < 0 1. H1: H1 > H2 2. Họ: H1 < H2 3. [t(n-1) , 0) H1: H1 – H2 > 0 Họ: 41 – H2 < 0 1. H;: H1 < H2 2. Ho: μι > μ2 3. [tin-1) , 0) H;: H1 – H2 < 0 Ho: 41 - H2 > 0
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