Identify the rejection region for testing the hypotheses with a=0.01. Select the correct choice below and fill in the answer box (Round to three decimal places as needed.)
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Q: alternate hypothesis (4.5,19,>19 or <19)
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- A humane society claims that less than 64% of households in a certain country own a pet. In a random sample of 400 households in that country, 244 say they own a pet. At a = 0.05, is there enough evidence to support the society's claim? Complete parts (a) through (c) below. (a) Identify the claim and state Ho and Ha Identify the claim in this scenario. Select the correct choice below and fill in the answer box to complete your choice. (Type an integer or a decimal. Do not round.) A. The percentage households in the country that own a pet is not %. OB. Less than % of households in the country own a pet. O C. % of households in the country own a pet. OD. More than % of households in the country own a pet. Let p be the population proportion of successes, where a success is a household in the country that owns a pet. State Ho and H₂ Select the correct choice below and fill in the answer boxes to complete your choice. (Round to two decimal places as needed.) OA. Ho-p² Ha p OE. Ho P= Ha: p=…A humane society claims that less than 68% of households in a certain country own a pet. In a random sample of 500 households in that country, 330 say they own a pet. At a = 0.01, is there enough evidence to support the society's claim? Complete parts (a) through (c) below. (Kound to two decimal places as needed.) OA. Ho P Ha: p² OD. Ho p Ha: p= OB. Ho: p2 Ha p Z= (Round to two decimal places as needed.) Identify the P-value. P=0 (Round to three decimal places as needed.). the null hypothesis. There OC. Ho: P Ha: p enough evidence to OF. Ho P > (c) Decide whether to reject or fail to reject the null hypothesis and (d) interpret the decision in the context of the original claim. Ha: ps the society's claim. NextAn education researcher claims that 57% of college students work year-round. In a random sample of 600 college students, 342 say they work year-round. At a = 0.05, is there enough evidence to reject the researcher's claim? Complete parts (a) through (e) below. (a) Identify the claim and state Ho and H3. Identify the claim in this scenario. Select the correct choice below and fill in the answer box to complete your choice. (Type an integer or a decimal. Do not round.) OA. % of college students work year-round. O B. At most % of college students work year-round. O C. The percentage of college students who work year-round is not O D. At least % of college students work year-round. Let p be the population proportion of successes, where a success is a college student who works year-round. State H, and Ha. Select the correct choice below and fill in the answer boxes to complete your choice. (Round to two decimal places as needed.) O A. Ho: p> O B. Ho: ps O C. Ho: p= Ha: ps Hại p> H3:p = O D.…
- Test the hypothesis using the P-value approach. Be sure to verify the requirements of the test. Ho: p=0.5 versus H: p>0.5 n= 100; x= 60; a= 0.01 Click here to view page 1 of the table Click here to view page 2 of the table. Calculate the test statistic, zo- (Round to two decimal places as needed.)A survey showed that 32% of human resource professionals are at companies that rejected job candidates because of information found on their social media. If 25 human resource professionals are randomly selected, would 14 be a significantly high number to be at companies that rejected job candidates because of information found on their social media? Why or why not? Select the correct choice below and fill in the answer box within your choice. (Round to four decimal places as needed.) OA. No, 14 would not be significantly high because the probability of 14 or more is OB. Yes, 14 would be significantly high because the probability of 14 or more is OC. Yes, 14 would be significantly high because the probability of 14 or more is D. No, 14 would not be significantly high because the probability of 14 or more is which is low. which is not low. which is low. which is not low.Claim: Most adults would erase all of their personal information online if they could. Asoftware firm survey of 640 randomly selected adults showed that 62% of them would erase all of their personal information online if they could. Find the value of the test statistic. The value of the test statistic is (Round to two decimal places as needed.)
- se the formula in this example to determine the sample size, n.The estimated prevalence is 18%, and the desired confidence level is 91% with a margin of error of 4%. (Round your answer to the nearest integer.)n =A marketing manager fora cell phone company claims that the percentage of children aged 8-12 who have cell phones differs from 61%. In a survey of 826 children aged 8-12 by a national consumers group, 545 of them had cell phones. Can you conclude that the managers claim is true? Use the a = 0.10 level of significance and the p value method with the ti 84 plus calculator. Compute the p value. Round the answers to at least four decimal places.The researchers from a study interviewed two random samples, one in 2015 and one in 2018. Both samples were asked "Have you read a print book in the last year?" Use the accompanying results from the study to complete parts (a) through (c). Read a print book Total 9 Yes 2521 1375 No Total 2015 1206 680 1886 p-value= (Round to three decimal places as needed.) 2018 1315 695 2010 a. Find and compare the sample proportions that had read a print book for these two groups. The sample proportion of the 2015 subjects that read a book within the last year is. The sample proportion of the 2018 subjects that read a book within the last year is (Round to four decimal places as needed.) The sample proportion for 2015 is b. Find a pooled estimate of the sample proportion. A pooled estimate of the sample proportion is (Round to four decimal places as needed.) c. Has the proportion who read print books increased? Find the observed value of the test statistic to test the hypotheses Ho: P₁ = P2 and Ha:…
- Determine the test statistic for this hypothesis test. (Round to two decimal places as needed.)Suppose are running a study/poll about the proportion of women over 40 who regularly have mammograms. You randomly sample 138 people and find that 91 of them match the condition you are testing.Suppose you are have the following null and alternative hypotheses for a test you are running:H0:p=0.67Ha:p>0.67Calculate the test statistic, rounded to 3 decimal places z=Use technology to find the P-value for the hypothesis test described below. The claim is that for 12 AM body temperatures, the mean is µ> 98.6°F. The sample size isn=9 and the test statistic is t=2.568. P-value = (Round to three decimal places as needed.)