Identify the regions under the t-distribution corresponding to the t-value. 1. When sample size n is 15 at 95% confidence level, what is the t-value?
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- 4..A p-value smaller than the significance level, a means.... O the statistic is unlikely/unusual/unexpected in the distribution O the statistic is likely/usual/expected in the distributionAssume the samples are random and independent, the populations are nomally distributed, and the population variances are equal. The table available below shows the prices (in dollars) for a sample of automobile batteries. The prices are classified according to battery type. At a = 0.10, is there enough evidence conclude that at least one mean battery price is different from the others? Complete parts (a) through (e) below. E Click the icon to view the battery cost data. (a) Let u1. P2. H3 represent the mean prices for the group size 35, 65, and 24/24F respectively. Identify the claim and state Ho and H. H Cost of batteries by type The claim is the V hypothesis. Group size 35 Group size 65 Group size 24/24F 101 111 121 124 D 146 173 182 278 124 140 141 89 (b) Find the critical value, Fo, and identify the rejection region. 90 79 84 The rejection region is F Fo, where Fo = (Round to two decimal places as needed.) (c) Find the test statistic F. Print Done F= (Round to two decimal places as…
- Construct a confidence interval for ud, the mean of the differences d for the population of paired data. Assume that the population of paired differences is normally distributed. If d = 3.125, Sd = 2.911, and n = 8, determine a 95 percent confidence interval for ud. 0.691 Hd <3.986 O 2.264 < d < 3.986 O 2.264 < d < 5.559 O 0.691 < d < 5.559PLEASE SHOW WORK.Explain how to find the critical values for a t-distribution. LOADING... Click the icon to view the t-distribution table. Question content area bottom Part 1 Give the first step. Choose the correct answer below. A. Identify the level of significance 1−α and the degrees of freedom, d.f.=n. B. Identify the level of significance α and the degrees of freedom, d.f.=n−1. C. Identify the level of significance α2 and the degrees of freedom, d.f.=n−1. D. Identify the level of significance 1−α2 and the degrees of freedom, df=n
- K Large samples of women and men are obtained, and the hemoglobin level is measured in each subject. Here is the 95% confidence interval for the difference between the two population means, where the measures from women correspond to population 1 and the measures from men correspond to population 2: -1.76 g/dLA random sample of statistics students were asked to estimate the total number of hours they spend watching television in an average week. The responses are recorded in Table. Use this sample data to construct a 98% confidence interval for the mean number of hours statistics students will spend watching television in one week. Assume the population is normally distributed. (Give your answer to 3 decimal places if necessary.) 20 13 1 10 20 0 10 13 16 10 1 17 18 3 9 (?,?)Can you fill out the blanks.You are interested in finding a 98% confidence interval for the average number of days of class that college students miss each year. The data below show the number of missed days for 14 randomly selected college students. Round answers to 3 decimal places where possible. 12 5 7 4 6 9 11 11 9 8 5 9 10 11 a. To compute the confidence interval use a distribution. b. With 98% confidence the population mean number of days of class that college students miss is between and days. c. If many groups of 14 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of missed class days and about percent will not contain the true population mean number of missedDetermine whether the following statements are True or False: If we increase the confidence level C, then the width of the CI decreases, i.e., the CI becomes narrower. (Hint: think about what happens to the margin of error m) Suppose the mean of a population µ = 100. If we found that the margin of error is m = 2 for level of confidence 98%, then we can be 98% confident that a sample mean (computed from a sample of the same size used to compute m) is in the interval (98, 102).The data below give the wait time in seconds for a random sample of callers when calling a local pizza restaurant. {66, 37, 4, 47, 12, 16, 62, 12, 21, 25, 49, 3} a. What is the point estimate for the average wait time for callers? b. Verify conditions for using this sample to predict population mean of wait times. Estimate the mean wait time for all callers to this restaurant, with 90% confidence. Write your answer as a sentence. C. d. Estimate the standard deviation of wait times for all callers to this restaurant, with 90% confidence. Write your answer as a sentence. (You do not need to check requirements.)SEE MORE QUESTIONS
