Identify the null and alternative hypotheses. Ho ▼ H₁ ▾▾ (Type integers or decimals. Do not round.) Identify the test statistic. (Round to two decimal places needed.) Identify the P-value. (Round to three decimal places as needed.) State the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. the null hypothesis. There sufficient evidence at the 0.01 significance level to the claim that the population mean of all wait times for the Tower of Terror ride at 5:00 PM is more than 30 minutes. Excel Display Difference

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### Hypothesis Testing Educational Example

A data set includes wait times (in minutes) for the Tower of Terror ride at Walt Disney World's Hollywood Studios theme park at 5:00 PM. Using 40 of these times to test the claim that the mean of all such wait times is more than 30 minutes, the following Excel display is obtained. Test the given claim using a 0.01 significance level.

**Excel Display Information:**
- **Difference**: 3
- **t (Observed value)**: 0.883
- **t (Critical value)**: 2.426
- **DF (Degrees of Freedom)**: 39
- **p-value (one-tailed)**: 0.191
- **alpha**: 0.01

### Instructions

**1. Identify the Null and Alternative Hypotheses:**
- \( H_0: \mu \le 30 \)
- \( H_1: \mu > 30 \)

**2. Identify the Test Statistic:**
- Test Statistic: 0.88 (rounded to two decimal places)

**3. Identify the P-value:**
- P-value: 0.191 (rounded to three decimal places)

**4. State the Conclusion about the Null Hypothesis:**
- [Reject/Fail to reject] the null hypothesis. There [is/is not] sufficient evidence at the 0.01 significance level to [support/reject] the claim that the population mean of all wait times for the Tower of Terror ride at 5:00 PM is more than 30 minutes.

### Graph Explanation:
The Excel display provides a table summarizing the results of a one-tailed t-test. The observed t-value is 0.883, which is less than the critical value of 2.426, resulting in a p-value of 0.191. Given that the p-value is larger than the significance level of 0.01, we do not reject the null hypothesis, indicating a lack of sufficient evidence to support the claim that the average wait time is greater than 30 minutes.
Transcribed Image Text:### Hypothesis Testing Educational Example A data set includes wait times (in minutes) for the Tower of Terror ride at Walt Disney World's Hollywood Studios theme park at 5:00 PM. Using 40 of these times to test the claim that the mean of all such wait times is more than 30 minutes, the following Excel display is obtained. Test the given claim using a 0.01 significance level. **Excel Display Information:** - **Difference**: 3 - **t (Observed value)**: 0.883 - **t (Critical value)**: 2.426 - **DF (Degrees of Freedom)**: 39 - **p-value (one-tailed)**: 0.191 - **alpha**: 0.01 ### Instructions **1. Identify the Null and Alternative Hypotheses:** - \( H_0: \mu \le 30 \) - \( H_1: \mu > 30 \) **2. Identify the Test Statistic:** - Test Statistic: 0.88 (rounded to two decimal places) **3. Identify the P-value:** - P-value: 0.191 (rounded to three decimal places) **4. State the Conclusion about the Null Hypothesis:** - [Reject/Fail to reject] the null hypothesis. There [is/is not] sufficient evidence at the 0.01 significance level to [support/reject] the claim that the population mean of all wait times for the Tower of Terror ride at 5:00 PM is more than 30 minutes. ### Graph Explanation: The Excel display provides a table summarizing the results of a one-tailed t-test. The observed t-value is 0.883, which is less than the critical value of 2.426, resulting in a p-value of 0.191. Given that the p-value is larger than the significance level of 0.01, we do not reject the null hypothesis, indicating a lack of sufficient evidence to support the claim that the average wait time is greater than 30 minutes.
Expert Solution
Step 1: Given Information:

It is given that in Excel display:

t( observed value) = test statistic, t = 0.883

t( critical value ) = 2.426

Df = 39

P-value = 0.191

Significance level, α = 0.01

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