Identifiers declared inside a block: scope { // block begins int x; // local in block x = 9; System.out.println (x) ; } // block ends have block scope, are called local variables and are visible only inside the block. Local variables in different blocks may have the same name. What is the output of the program? public static void main (String [] a) { int x; // local in main } } x = 1 ; System.out.println("Main x " + x); methodl () ; void methodl () { } System.out.println("Main x " + x); method2 () ; int x= 0; // local in method System.out.println ("methodl x"+ x); void method2 () { System.out.println ("method2 x"+ x);
Identifiers declared inside a block: scope { // block begins int x; // local in block x = 9; System.out.println (x) ; } // block ends have block scope, are called local variables and are visible only inside the block. Local variables in different blocks may have the same name. What is the output of the program? public static void main (String [] a) { int x; // local in main } } x = 1 ; System.out.println("Main x " + x); methodl () ; void methodl () { } System.out.println("Main x " + x); method2 () ; int x= 0; // local in method System.out.println ("methodl x"+ x); void method2 () { System.out.println ("method2 x"+ x);
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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I find these types of questions challenging due to a lack of understanding. Could you kindly provide a detailed and specific answer to assist me to answer the question below.
question:
Local variables in different blocks may have the same name. What is the output of the program?
![Identifiers declared inside a block:
scope
{ // block begins
int x; // local in block
X
x = 9;
System.out.println (x) ;
} // block ends
have block scope, are called local
variables and are visible only inside
the block.
Local variables in different blocks
may have the same name.
What is the output of the
program?
public static void main (String[] a)
{
}
}
int x; // local in main
}
x = 1 ;
void methodl ()
{
System.out.println("Main x " + x);
methodl () ;
System.out.println ("Main x " + x);
method2 () ;
int x = 0; // local in method
System.out.println("methodl x"+ x);
void method2 ()
{
System.out.println("method2 x"+ x);](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2318e523-864b-4b5c-b102-098ecff48e9d%2Fe95a23f3-c627-4d35-9f03-685eb4f15610%2F06zk4s_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Identifiers declared inside a block:
scope
{ // block begins
int x; // local in block
X
x = 9;
System.out.println (x) ;
} // block ends
have block scope, are called local
variables and are visible only inside
the block.
Local variables in different blocks
may have the same name.
What is the output of the
program?
public static void main (String[] a)
{
}
}
int x; // local in main
}
x = 1 ;
void methodl ()
{
System.out.println("Main x " + x);
methodl () ;
System.out.println ("Main x " + x);
method2 () ;
int x = 0; // local in method
System.out.println("methodl x"+ x);
void method2 ()
{
System.out.println("method2 x"+ x);
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