ICL ANOOTHER A spaceship is traveling through deep space towards a space station and needs to make a course correction to go around a nebula. The captain orders the ship to travel 3.1 x 106 kilometers before turning 70° and traveling 1.3 x 106 kilometers before assuming the path towards the space station. If the captain had not ordered a course correction, what would have been the magnitude (in kilometers) and direction (in degrees counterclockwise from the +x-axis) of the path of the spaceship if it had traveled through the nebula? space station nebula spaceship magnitude km direction ° counterclockwise from the +x-axis Additional Materials O Reading Tutorial

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### Navigational Challenge in Deep Space

A spaceship is traveling through deep space towards a space station and needs to make a course correction to go around a nebula. The captain orders the ship to travel \( 3.1 \times 10^6 \) kilometers before turning 70° and traveling \( 1.3 \times 10^6 \) kilometers before assuming the path towards the space station. If the captain had not ordered a course correction, what would have been the magnitude (in kilometers) and direction (in degrees counterclockwise from the +x-axis) of the path of the spaceship if it had traveled through the nebula?

#### Diagram Explanation
The diagram accompanying the problem shows:

- A coordinate plane with x and y axes labeled.
- A spaceship starting from the origin of the coordinate system.
- A vector, labeled \( \vec{A} \), representing the initial travel distance of \( 3.1 \times 10^6 \) kilometers in the positive x-direction.
- At the end of vector \( \vec{A} \), the spaceship turns 70° counterclockwise from its current direction and travels another distance, \( \vec{B} \), of \( 1.3 \times 10^6 \) kilometers towards the space station, represented by another vector.
- A nebula is visually represented but not marked with specific coordinates.
- The space station is positioned at the end of vector \( \vec{B} \).
- An angle \( \theta \) is marked between the resultant vector and the +x-axis, which needs to be calculated.

#### Input Fields
Below the diagram, there are two input fields:
- Magnitude: ____ km
- Direction: ____ ° counterclockwise from the +x-axis

#### Additional Materials
- Reading
- Tutorial

These resources are provided to aid in the understanding and solving of the problem.
Transcribed Image Text:### Navigational Challenge in Deep Space A spaceship is traveling through deep space towards a space station and needs to make a course correction to go around a nebula. The captain orders the ship to travel \( 3.1 \times 10^6 \) kilometers before turning 70° and traveling \( 1.3 \times 10^6 \) kilometers before assuming the path towards the space station. If the captain had not ordered a course correction, what would have been the magnitude (in kilometers) and direction (in degrees counterclockwise from the +x-axis) of the path of the spaceship if it had traveled through the nebula? #### Diagram Explanation The diagram accompanying the problem shows: - A coordinate plane with x and y axes labeled. - A spaceship starting from the origin of the coordinate system. - A vector, labeled \( \vec{A} \), representing the initial travel distance of \( 3.1 \times 10^6 \) kilometers in the positive x-direction. - At the end of vector \( \vec{A} \), the spaceship turns 70° counterclockwise from its current direction and travels another distance, \( \vec{B} \), of \( 1.3 \times 10^6 \) kilometers towards the space station, represented by another vector. - A nebula is visually represented but not marked with specific coordinates. - The space station is positioned at the end of vector \( \vec{B} \). - An angle \( \theta \) is marked between the resultant vector and the +x-axis, which needs to be calculated. #### Input Fields Below the diagram, there are two input fields: - Magnitude: ____ km - Direction: ____ ° counterclockwise from the +x-axis #### Additional Materials - Reading - Tutorial These resources are provided to aid in the understanding and solving of the problem.
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