Please help me with this HW. PLEASE show all the steps! THANKS Consider:F= GM,m, -for whichM, and m2 refer to point MASSES measured in kilograms,K.Q.q2F.= +for whichQ, and q2 refer to point CHARGES measured in Coulombs.K. z 8.99× 10° Nm?and e = qpreten =-q.hetren z 1.60 × 10 "Coulombs.NOTE: According to a tradition that developed FOR CONVENIENCE(but which may well right now seem incredibly INCONVENIENT). . :1K. is generally written, instead, as:Απε.C²for which: E, z 8.85× 10-12.Nm² ·1(4)(3.14...)(8.85 × 10 ")That is.= 8.99 x 10',(so both expressions stand for the same numerical value).but, for reasons that might not yet seem clear.the arrangement on the left side allows for the cancellation of certain terms,and thereby emphasizes certain others.Page 1 of 3A)GIVEN THE ABOVE,Assume we have a POSITIVE POINT CHARGE of 50 Coulombssitting at the origin of some coordinate system (in the lab).It will exert an electrostatic force an any and all charges that might be found at any locations in space.Let's CALL THIS the "SOURCE" of such olectrostatie forces.Imagine a much smaller point chargo that we place at some known distance from the source --The source will exert an electrostatic force on this smaller point chargo.Call this smallor point charge the "tost chargo".DO THE NEXT five oxorcisos in ANY ORDER you find most convenient.Solve for the electrostatic force exerted by the source charge onto the test charge if:i. The test charge is +3 Coulombs and is 5 meters away from the source charge.ii. The test charge is – 6 Coulombs and is 5 meters away from the source charge.iii. The test charge is +5 Coulombs and is 5 meters away.iv. The test charge is + 1 Coulombs and is 5 meters away.v. The test charge is – 2 Coulombs and is 5 meters away.So. lotE.Electrostatie FORCE per CHARGE = [Nowtons/Coulomb]924tɛ, p²1 Q-E. = FE. = The Electrostatic FIELD: i. The test charge is + 3 Coulombs and is 5 meters away from the source charge.ii. The test charge is – 6 Coulombs and is 5 meters away from the source charge.i. The test charge is +5 Coulombs and is 5 meters away.iv. The test charge is +1 Coulombs andis 5 meters away.v. The test charge is – 2 Coulombs and is 5 meters away.So. lotE == Eloctrostatic FORCE por CHARGE = [Newtons/Coulomb]|1 Q.4:~E =F.1 Q:E. = The Electrostatie FIELD:A charge (the source charge) exerts an electrostatie force onto ANOTHER charge (the tost chargo).A chargo (the source charge) exerts an ELECTROSTATIC FIELD onto a POINT in SPACE.Then the FIELD exorts a force on any chargo locatod at that point (the test charge).THUS.The ELECTROSTATIC FIELD is:the amount of FORCEthat aknown SOURCEcharge WOULDlorwill) exertat aknown distance from atestcharge--alwaysdefined tobe+ICoulombof charge.Page 2 of 3B) E-FIELDS FROMPOINTCHARGES (25 PTS).Two point-charges of differing magnitudes are held stationary in anenormously spacious x-y plane.NORTH (X(0.0)EAST (+WEST (-)SOUTH (-)The strengths and locations of the charges are organized into a table, below.A researcher places an instrument called a 'field detector' at the point (0,0).The detector is designed to measure electrostatic field magnitudes and directions.Name|Charge x-Coordinate|y-Coordinate|Ordered Pair|Q1543(5,0)(10,0)Q2-210Location of Interest: (0,0)Note: All coordinates are measured and given in meters;the (very very large) charge magnitudesare given in Coulombs.Also Note: The Coulomb constant for electrostatic interactioncan be very reasonably approximated by this value:9 Noy?K. - 9 x 10°Draw a neat and clear sketch of the situation, as you understand it.Your sketch must express a clear decision as to which direction willbe designated positive and which direction will be negative (5 pts).Page 3 of 3.

Since you have asked multiple questions we will solve first question for you . If you want any…

i. The test charge is +3 Coulombs and is 5 meters away from the source charge. i. The test charge is -6Coulombs and is 5 meters away from the source charge. i. The test charge is +5 Coulombs and is 5 meters away. iv. The test charge is +1Coulombs and is 5 meters away. v. The test charge is – 2 Coulombs and is 5 meters away.

i. The test charge is +3 Coulombs and is 5 meters away from the source charge. i. The test charge is -6Coulombs and is 5 meters away from the source charge. i. The test charge is +5 Coulombs and is 5 meters away. iv. The test charge is +1Coulombs and is 5 meters away. v. The test charge is – 2 Coulombs and is 5 meters away.