#6 Resolve for one mean T procedure 19A new drug results in lowering the heart rate by varying amounts. In a test of the effectiveness of the drug,22 subjects were treated and their heart rates were measured after the treatment. The drops in theirheart rates have a mean of 6 beats per minute and a standard deviation of 2.61 beats perminute. Construct a 90% confidence interval for the average decrease in the heart rate after using the newdrug. You may assume that the sample is from a normal population.i. Procedure: One mean T procedure✓✓oii. Assumptions: (select everything that applies)Normal populationSimple random samplePopulation standard deviation is knownSample size is greater than 30The number of positive and negative responses are both greater than 10Population standard deviation is unknowniii. Unknown parameter: u, population mean Viv. Point estimate: sample mean, X ✓✓decimal places)v. Confidence level0% and a =aand 1XX22o Critical values: (Round the answer to 3 decimal places)right-also▪left=Part 2 of 5beats per minute (Round the answer to 2

Let be the population mean beats per minute.Given that,No. of subjects Sample mean Sample standard…

Answered: i. Procedure: One mean T procedure ✓o…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Question

#6 Resolve for one mean T procedure

19
A new drug results in lowering the heart rate by varying amounts. In a test of the effectiveness of the drug,
22 subjects were treated and their heart rates were measured after the treatment. The drops in their
heart rates have a mean of 6 beats per minute and a standard deviation of 2.61 beats per
minute. Construct a 90% confidence interval for the average decrease in the heart rate after using the new
drug. You may assume that the sample is from a normal population.
i. Procedure: One mean T procedure
✓✓o
ii. Assumptions: (select everything that applies)
Normal population
Simple random sample
Population standard deviation is known
Sample size is greater than 30
The number of positive and negative responses are both greater than 10
Population standard deviation is unknown
iii. Unknown parameter: u, population mean V
iv. Point estimate: sample mean, X ✓✓
decimal places)
v. Confidence level
0
% and a =
a
and 1
XX
2
2
o Critical values: (Round the answer to 3 decimal places)
right-
also
▪left=
Part 2 of 5
beats per minute (Round the answer to 2

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

Expert Solution