. Find the equivalent capacitance in the following circuit.2. Compute the capacitance of a parallel-plate having rectangular plates of 64cm by 42 cm. These plates are placed between a porcelain dielectric (Er=2.6) with a separation of 0.3cm. If a voltage of 55V is applied to the capacitor, how much energy can the capacitor store.. 247.32µF18.42µF74.38µFi.ii.iii.iv.37.5µF70 uF4nF100 µF96 µF200 μF_25 µFCeq2.Compute the capacitance of a parallel-plate capacitor havingrectangular plates of 64 cm by 42 cm. These plates are place between a porcelaindielectric (e, = 2.6) with a separation of 0.3 cm. If a voltage of 55V is applied to thecapacitor, how much energy the capacitor store?C = 183.5pF, w = 52.9 nJC = 2.06nF, w = 3.12 µlC= 233.13F, w = 352kJC = 20.6 µF, w = 3.12 mJi.%3Dii.iii.iv.

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Answered: i. 247.32µF 18.42µF 74.38µF ii. iii.…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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. Find the equivalent capacitance in the following circuit. 2. Compute the capacitance of a parallel-plate having rectangular plates of 64cm by 42 cm. These plates are placed between a porcelain dielectric (Er=2.6) with a separation of 0.3cm. If a voltage of 55V is applied to the capacitor, how much energy can the capacitor store ..

247.32µF
18.42µF
74.38µF
i.
ii.
iii.
iv.
37.5µF
70 uF
4nF
100 µF
96 µF
200 μF_
25 µF
Ceq
2.
Compute the capacitance of a parallel-plate capacitor having
rectangular plates of 64 cm by 42 cm. These plates are place between a porcelain
dielectric (e, = 2.6) with a separation of 0.3 cm. If a voltage of 55V is applied to the
capacitor, how much energy the capacitor store?
C = 183.5pF, w = 52.9 nJ
C = 2.06nF, w = 3.12 µl
C= 233.13F, w = 352kJ
C = 20.6 µF, w = 3.12 mJ
i.
%3D
ii.
iii.
iv.

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