I section steel profile is not symmetrical as shown. If the tensile stress on the upper side of the flange shall not exceed 17.5 MPa. calculate the bending moment acting on the cross section? If the cross section acts as a cross section of 100 kN, draw the shear stress distribution! 25 cm 1264.0376 kN/m2 5 cm 6320.1882 kN/m2 7354.4887 kN/m? 5172.693 kN/m2 5 cm 15 cm 17.24.31 kN/m2 (a) (b) Solution key: Moment of bending = M = 57 829,827 Nm The shear stress distribution is shown in Figure (b). 35 cm
I section steel profile is not symmetrical as shown. If the tensile stress on the upper side of the flange shall not exceed 17.5 MPa. calculate the bending moment acting on the cross section? If the cross section acts as a cross section of 100 kN, draw the shear stress distribution! 25 cm 1264.0376 kN/m2 5 cm 6320.1882 kN/m2 7354.4887 kN/m? 5172.693 kN/m2 5 cm 15 cm 17.24.31 kN/m2 (a) (b) Solution key: Moment of bending = M = 57 829,827 Nm The shear stress distribution is shown in Figure (b). 35 cm
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:I section steel profile is not symmetrical as shown. If the tensile stress
on the upper side of the flange shall not exceed 17.5 MPa. calculate the
bending moment acting on the cross section? If the cross section acts
as a cross section of 100 kN, draw the shear stress distribution!
25 cm
1264.0376 kN/m2
5 cm
6320.1882 kN/m²
7354.4887 kN/m?
5172.693 kN/m2
5 cm
15 cm
17.24.31 kN/m²
(a)
(b)
Solution key:
Moment of bending = M = 57 829,827 Nm
The shear stress distribution is shown in Figure (b).
5 cm
35 cm
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