23 1 **Problem Description:**A 0.038-kg pet lab mouse sits on a 0.35-kg air-track cart, as shown in Figure 1. The cart is at rest, as is a second cart with a mass of 0.25 kg. The lab mouse now jumps to the second cart. After the jump, the 0.35-kg cart has a speed of \( v_1 = 0.88 \, \text{m/s} \).**Figure Overview:**- *Figure 1:* - **(a) Before the jump:** - The 0.35-kg cart and the 0.25-kg cart are stationary on an air track. The mouse is on the 0.35-kg cart. - **(b) After the jump:** - The 0.35-kg cart is moving to the left with velocity \( v_1 = 0.88 \, \text{m/s} \). - The mouse has jumped to the 0.25-kg cart, which is now moving to the right with velocity \( v_2 \).**Question (Part A):**What is the speed \( v_2 \) of the mouse and the 0.25-kg cart?*Express your answer to two significant figures and include appropriate units.***Interactive Box:**- Input fields for Value and Units.- A "Submit" button for answer submission.- Option to "Request Answer" for assistance if needed.**User Actions:**- Students can enter their calculated value and unit to find the speed \( v_2 \).- After entering the response, students click "Submit" to check their answer.- Feedback and assistance are available upon request.**Navigation:**- Buttons for "Provide Feedback" and "Next" to move through sections or pages.

Name: 23 1 **Problem Description:**A 0.038-kg pet lab mouse sits on a 0.35-k
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Description: 23 1 **Problem Description:**A 0.038-kg pet lab mouse sits on a 0.35-kg air-track cart, as shown in Figure 1. The cart is at rest, as is a second cart with a mass of 0.25 kg. The lab mouse now jumps to the second cart. After the jump, the 0.35-kg car

To solve the given question we will use the conservation of momentum.We will take the direction to the right as positive and to the left as negative. Before the jump, everything is at rest. Hence, the initial total momentum is zero. After the jump, the ice with a mass of 0.35 kg went to the left with a velocity of -0.88 m/s and the other ice with the pet goes to the right with a velocity of v2. Using conservation of momentum we get: Initial total momentum= Final total momentum 0=0.35(-0.88)+(0.25+0.038)v2v2=0.35×0.880.288v2=1.07 m/s Hence, after the jump, the value of v2 is 1.07 m/s.

Science

Physics

i Rev A 0.038-kg pet lab mouse sits on a 0.35-kg air-track cart, as shown in (Figure 1). The cart is at rest, as is a second cart with a mass of 0.25 kg. The lab mouse now jumps to the second cart. After the jump, the 0.35-kg cart has a speed of vi = 0.88 m/s. Part A What is the speed v2 of the mouse and the 0.25-kg cart? Express your answer to two significant figures and include appropriate units. µA Figure < 1 of 1 Value Units Submit Request Answer 0.35 kg 0.25 kg| (a) Before the jump Provide Feedback Ne V1 V2 0.35 kg 0.25 kg (b) After the jump

i Rev A 0.038-kg pet lab mouse sits on a 0.35-kg air-track cart, as shown in (Figure 1). The cart is at rest, as is a second cart with a mass of 0.25 kg. The lab mouse now jumps to the second cart. After the jump, the 0.35-kg cart has a speed of vi = 0.88 m/s. Part A What is the speed v2 of the mouse and the 0.25-kg cart? Express your answer to two significant figures and include appropriate units. µA Figure < 1 of 1 Value Units Submit Request Answer 0.35 kg 0.25 kg| (a) Before the jump Provide Feedback Ne V1 V2 0.35 kg 0.25 kg (b) After the jump

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Problem 4: Speed deamplifier. In the figure above on the right, block 1 of mass m1 slides along an x-axis on a frictionless floor at speed 4 m/sec.Then it undergoes a one-dimensional elastic collision with stationary block 2 of mass m2 = 2m1. Next, block 2 undergoes a one-dimensional elastic collision with stationary block 3 of mass mz = 4m1. What then is the speed of block 3? Answer: 16 m/sec or 1.78 m/sec.