I received the task to determine vectorially and explain how to obtain the angle of 109.5 degrees in the tetrahedral geometry? for covalent crystals.
Good morning I am recently studying the topic of covalent crystals, I received the task to determine vectorially and explain how to obtain the angle of 109.5 degrees in the tetrahedral geometry? for covalent crystals.
Here I share a slide with the information and a small scheme.
Thank you very much in advance.
If we put the atom in the four alternate corner of a cube then a tetrahedral structure is formed.
The atoms position are denoted by A,B,C and D and O is the central point whose position coordinate is (0,0,0)
So the position coordinate of A =(1,-1,1)
the position coordinate of B = (1,1,-1)
the position coordinate of C = (-1,1,1)
the position coordinate of B = (1,1,-1)
OA represented by vector 'a'
OB represented by vector 'b'
And let the angle between them is .
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