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I need a detailed expiration of the steps -jwo ⇒ X(z) = 1½ ½ e² h=3 (n-1) (ae)" + eb (n-1) (ae tub=") ^ 2 h=3 Now, to make the Series Start from n=o, substract the terms for n=0, 1, 2. = X(2) = 1 - (n-1) (a Z = 1)" +1-(awo = 1)² n=o + lewo 2 (n-1) (ae wo = 1) " +1 - (aejwo=1) n=0 n Jub = X (2) = 1 = 10 (n-1)(ae + (n-1) (aewoźn Σ n=0 +! (elwo+ewo) +160 2 n=o a² (evote two). 2-2 2 2 ⇒ X(z) = 1 =¯¯ {* (n-1)(ae¹²='" + Wo e (n-1) (a 2 n=o + Coswo - a²coswo. 22 n=o -2

I need a detailed expiration of the steps -jwo ⇒ X(z) = 1½ ½ e² h=3 (n-1) (ae)" + eb (n-1) (ae tub=") ^ 2 h=3 Now, to make the Series Start from n=o, substract the terms for n=0, 1, 2. = X(2) = 1 - (n-1) (a Z = 1)" +1-(awo = 1)² n=o + lewo 2 (n-1) (ae wo = 1) " +1 - (aejwo=1) n=0 n Jub = X (2) = 1 = 10 (n-1)(ae + (n-1) (aewoźn Σ n=0 +! (elwo+ewo) +160 2 n=o a² (evote two). 2-2 2 2 ⇒ X(z) = 1 =¯¯ {* (n-1)(ae¹²='" + Wo e (n-1) (a 2 n=o + Coswo - a²coswo. 22 n=o -2

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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I need a detailed expiration of the steps -jwo ⇒ X(z) = 1½ ½ e² h=3 (n-1) (ae)" + eb (n-1) (ae tub=") ^ 2 h=3 Now, to make the Series Start from n=o, substract the terms for n=0, 1, 2. = X(2) = 1 - (n-1) (a Z = 1)" +1-(awo = 1)² n=o + lewo 2 (n-1) (ae wo = 1) " +1 - (aejwo=1) n=0 n Jub = X (2) = 1 = 10 (n-1)(ae + (n-1) (aewoźn Σ n=0 +! (elwo+ewo) +160 2 n=o a² (evote two). 2-2 2 2 ⇒ X(z) = 1 =¯¯ {* (n-1)(ae¹²='" + Wo e (n-1) (a 2 n=o + Coswo - a²coswo. 22 n=o -2
Transcribed Image Text:I need a detailed expiration of the steps -jwo ⇒ X(z) = 1½ ½ e² h=3 (n-1) (ae)" + eb (n-1) (ae tub=") ^ 2 h=3 Now, to make the Series Start from n=o, substract the terms for n=0, 1, 2. = X(2) = 1 - (n-1) (a Z = 1)" +1-(awo = 1)² n=o + lewo 2 (n-1) (ae wo = 1) " +1 - (aejwo=1) n=0 n Jub = X (2) = 1 = 10 (n-1)(ae + (n-1) (aewoźn Σ n=0 +! (elwo+ewo) +160 2 n=o a² (evote two). 2-2 2 2 ⇒ X(z) = 1 =¯¯ {* (n-1)(ae¹²='" + Wo e (n-1) (a 2 n=o + Coswo - a²coswo. 22 n=o -2
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