I -н -н I н. I ОН ОН ОН CH₂OH I I CH₂OH :0 Но НО CH₂OH

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Draw the electron pushing mechanism 

The image illustrates a chemical reaction involving two structural diagrams of sugar molecules, specifically an isomerization process.

**Left Structure:**

- The molecule shown is an open-chain form of a sugar, featuring an aldehyde group at the top (indicated by the C=O bond) and multiple hydroxyl (OH) groups along the carbon chain.
- It consists of five carbon atoms in a linear arrangement. The carbon atoms are connected by single bonds, with each carbon atom bearing one or more hydrogen atoms (H) and hydroxyl groups (OH).
- The structure includes a terminal CH₂OH group at the bottom.

**Arrow:**

- The arrow indicates a chemical transformation or reaction, shifting from one structural isomer to another.

**Right Structure:**

- This structure is the open-chain form of a different sugar isomer, featuring a ketone group (indicated by the C=O bond) on the second carbon from the top.
- Similar to the left structure, it also consists of five carbon atoms in a linear arrangement, each bonded to hydrogen (H) or hydroxyl (OH) groups.
- Both the top and bottom of the chain end with CH₂OH groups.

This isomerization represents an enolization process common in carbohydrate chemistry, transforming an aldose form of a sugar into a ketose form.
Transcribed Image Text:The image illustrates a chemical reaction involving two structural diagrams of sugar molecules, specifically an isomerization process. **Left Structure:** - The molecule shown is an open-chain form of a sugar, featuring an aldehyde group at the top (indicated by the C=O bond) and multiple hydroxyl (OH) groups along the carbon chain. - It consists of five carbon atoms in a linear arrangement. The carbon atoms are connected by single bonds, with each carbon atom bearing one or more hydrogen atoms (H) and hydroxyl groups (OH). - The structure includes a terminal CH₂OH group at the bottom. **Arrow:** - The arrow indicates a chemical transformation or reaction, shifting from one structural isomer to another. **Right Structure:** - This structure is the open-chain form of a different sugar isomer, featuring a ketone group (indicated by the C=O bond) on the second carbon from the top. - Similar to the left structure, it also consists of five carbon atoms in a linear arrangement, each bonded to hydrogen (H) or hydroxyl (OH) groups. - Both the top and bottom of the chain end with CH₂OH groups. This isomerization represents an enolization process common in carbohydrate chemistry, transforming an aldose form of a sugar into a ketose form.
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