j,k,l Derivatives Rules1. Fill in the blanks:(a) (c) ==(c) a (x¹) =(e) [f(g(x))]=(i)(k)dxdx(q).(sin x) =(tan x) =dx(sec x)(m) (ex) =d(0) (logax):dx=ddx(sin¯¹ x) =(b) & (x) =(d) [f(x) · g(x)] =©. [*]·=(h) 4 (cos x) :=(j) (csc x) =(1) & (cot x) =(n) (lnx)(P) & (a*) =dx(r)ddx(tan-¹ x) =

Answered: (i) (k) dx (tan x) dx (secx) = = (j)…

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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Question

j,k,l

Derivatives Rules
1. Fill in the blanks:
(a) (c) =
=
(c) a (x¹) =
(e) [f(g(x))]=
(i)
(k)
dx
dx
(q).
(sin x) =
(tan x) =
dx
(sec x)
(m) (ex) =
d
(0) (logax):
dx
=
d
dx
(sin¯¹ x) =
(b) & (x) =
(d) [f(x) · g(x)] =
©. [*]·
=
(h) 4 (cos x) :
=
(j) (csc x) =
(1) & (cot x) =
(n) (lnx)
(P) & (a*) =
dx
(r)
d
dx
(tan-¹ x) =

Expert Solution

Step 1: Define the given problem.

As per your request, we answer only parts (j) , (k) and (l).

find using derivative rules

$open parentheses j close parentheses space fraction numerator d space over denominator d x end fraction open parentheses c s c x close parentheses equals ? open parentheses k close parentheses space fraction numerator d space over denominator d x end fraction open parentheses s e c x close parentheses equals ? open parentheses l close parentheses space fraction numerator d space over denominator d x end fraction open parentheses c o t x close parentheses equals ?$