Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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I just need this checked and corrected please
![Consider the curve y = ½³ from x = 0 to x = 3
(a) Write down but DO NOT EVALUATE an integral for arclength of this curve wrt x.
(b) Write down but DO NOT EVALUATE an integral for arclength of this curve wrt y.
(c) Write down but DO NOT EVALUATE an integral for the surface area of the shape created by
revolving this curve around the x-axis wrt x.
(d) Write down but DO NOT EVALUATE an integral for the surface area of the shape created by
revolving this curve around the x-axis wrt y.
(e) Choose one of either (c) or (d) and evaluate it.
Q2) consider the curve y₁ = x² from X=0 to x=3
@arclength
WRT X
L=
√1 + (x²³) ² dx
dy
dy
arclength WRT Y.
dy
व
3√34 = x
-x²
dx = (34) 3
dy
-43
dx = 13 (37) 73
dy
3
2기
Choose
2π
S² 271 1׳3 √1+x+ dx
U=1+x4
х
и
du=4x34x
Z
82
du=x³dx.
о
L:
SA-527yL
9
b
9
√3492
1 2 3
3
X=1
9
X=37=9
radius is y
1+
revolving x-axis
82
182
-> qaπ [(1+ (82)4) 2/2-(1+41)98%]
aπ[ (1+820) -(2)%]
2
27½ u² du
foπ uz du.
182
[dz (1) |]
13/282](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1a0802a2-9dd1-43c0-9b3f-3c3accbadbd6%2F1a326068-3981-4d9d-a142-afc80a0cf316%2Fxiam5e_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Consider the curve y = ½³ from x = 0 to x = 3
(a) Write down but DO NOT EVALUATE an integral for arclength of this curve wrt x.
(b) Write down but DO NOT EVALUATE an integral for arclength of this curve wrt y.
(c) Write down but DO NOT EVALUATE an integral for the surface area of the shape created by
revolving this curve around the x-axis wrt x.
(d) Write down but DO NOT EVALUATE an integral for the surface area of the shape created by
revolving this curve around the x-axis wrt y.
(e) Choose one of either (c) or (d) and evaluate it.
Q2) consider the curve y₁ = x² from X=0 to x=3
@arclength
WRT X
L=
√1 + (x²³) ² dx
dy
dy
arclength WRT Y.
dy
व
3√34 = x
-x²
dx = (34) 3
dy
-43
dx = 13 (37) 73
dy
3
2기
Choose
2π
S² 271 1׳3 √1+x+ dx
U=1+x4
х
и
du=4x34x
Z
82
du=x³dx.
о
L:
SA-527yL
9
b
9
√3492
1 2 3
3
X=1
9
X=37=9
radius is y
1+
revolving x-axis
82
182
-> qaπ [(1+ (82)4) 2/2-(1+41)98%]
aπ[ (1+820) -(2)%]
2
27½ u² du
foπ uz du.
182
[dz (1) |]
13/282
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