I have the question and the answer can someone go line by line to explain the logic of the code and explain the concepts and how I am supposed to get the output #include float x = 32.0; void main() { int x = 23; float y; float f(int); printf("%d %f\n", x, f(x/2)); y = f(x/2); printf("%d %f", x, y); } float f(const int n) { static int k = 0; x = x/2.0; k++; return (x+n)/k; } output (format not important, values are important): 23 27.000000 23 9.500000
Operations
In mathematics and computer science, an operation is an event that is carried out to satisfy a given task. Basic operations of a computer system are input, processing, output, storage, and control.
Basic Operators
An operator is a symbol that indicates an operation to be performed. We are familiar with operators in mathematics; operators used in computer programming are—in many ways—similar to mathematical operators.
Division Operator
We all learnt about division—and the division operator—in school. You probably know of both these symbols as representing division:
Modulus Operator
Modulus can be represented either as (mod or modulo) in computing operation. Modulus comes under arithmetic operations. Any number or variable which produces absolute value is modulus functionality. Magnitude of any function is totally changed by modulo operator as it changes even negative value to positive.
Operators
In the realm of programming, operators refer to the symbols that perform some function. They are tasked with instructing the compiler on the type of action that needs to be performed on the values passed as operands. Operators can be used in mathematical formulas and equations. In programming languages like Python, C, and Java, a variety of operators are defined.
I have the question and the answer can someone go line by line to explain the logic of the code and explain the concepts and how I am supposed to get the output
#include <stdio.h>
float x = 32.0;
void main() {
int x = 23;
float y;
float f(int);
printf("%d %f\n", x, f(x/2));
y = f(x/2);
printf("%d %f", x, y);
}
float f(const int n) {
static int k = 0;
x = x/2.0;
k++;
return (x+n)/k;
}
output (format not important, values are important):
23 27.000000
23 9.500000
Step by step
Solved in 2 steps with 1 images
