I have the following data from an NMR scan. Five peaks; a doublet at about 0.8ppm (6H) a small single septet at about 1.5 ppm (1H), a triplet at 1.6 ppm (2H(, a singlet at about 2.1 ppm (3H), a triplet at about 4.4 ppm (2H). The molecular formula is C7H14O2. I calculated a degree of unsaturation of 1.

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter12: Structure Determination: Mass Spectrometry And Infrared Spectroscopy

Section12.SE: Something Extra

Problem 16AP: Camphor, a saturated monoketone from the Asian camphor tree, is used among other things as a moth...

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I have the following data from an NMR scan. Five peaks; a doublet at about 0.8ppm (6H) a small single septet at about 1.5 ppm (1H), a triplet at 1.6 ppm (2H(, a singlet at about 2.1 ppm (3H), a triplet at about 4.4 ppm (2H). The molecular formula is C₇H₁₄O₂. I calculated a degree of unsaturation of 1. I have tentatively identified the compound as methyl-4-methylbutanoate. I would appreciate any comments you care to make. Thank you.

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