i have attached solved format  Note: My previous homework was cancelled due to not following format.   i want to give you thumbs up. So please

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Please solve homework in the following format like in two columns: 

 

•statment          |             •justifications 



i have attached solved format 

Note: My previous homework was cancelled due to not following format.

 

i want to give you thumbs up. So please follow attached format

Format/example
Stat ement
jushifiation
> Given e>o 3 6,>0, &70 such that
» BY the definition
IfW) - f(x.)] < %4 wheneves x-4,| < 8,
of Continuity
|< <q wheneves -,] < Sz
> since fi, S2>0, we
Can take min S6,,2
2> Let 8: min { $i,8,}
3> PROPESH1 of mod ulus
and simple algeusa
3> for 1X- X,1 < 8 , we have
E/2 + 6/2 : €
> Hence (2f+48) is Continuons at X, 9 BY the defininion o0
Confinu ous.
Transcribed Image Text:Format/example Stat ement jushifiation > Given e>o 3 6,>0, &70 such that » BY the definition IfW) - f(x.)] < %4 wheneves x-4,| < 8, of Continuity |< <q wheneves -,] < Sz > since fi, S2>0, we Can take min S6,,2 2> Let 8: min { $i,8,} 3> PROPESH1 of mod ulus and simple algeusa 3> for 1X- X,1 < 8 , we have E/2 + 6/2 : € > Hence (2f+48) is Continuons at X, 9 BY the defininion o0 Confinu ous.
Poove (9n theorem
foomat)
of lim fc)= 2 and
lim grx)= 1
%3D
then
lim 24(x)+4g(x) =8
Answer:
státement
Justification.
Transcribed Image Text:Poove (9n theorem foomat) of lim fc)= 2 and lim grx)= 1 %3D then lim 24(x)+4g(x) =8 Answer: státement Justification.
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