I- EVALÚA LAS SIGUIENTES POTENCIAS RECUERDA ESCRIBIR EL PROCEDIMIENTO. MIRA EL EJEMPLO 32 = 3• 3 = 9 a) 53 = b) 34 = c) x* . x6 = d) a12. at = e) 5-8. 53= f) (4* )2 g) (3?)2. Il- HALLA LAS RAICES CUADRADAS Y CUBICAS SEGÚN SE SOLICITE CONTESTARÁS COMO EN ESTE EJEMPLO: J4 = 2 (porque 22 = 2 x 2 = 4) 27 V9 = श = V16 = %3D V25 = %3D 36 = 49 125 %3D V64 = 343 81= 216 100 = 121 %3D 512 %3D 144 %3D 169 =
I- EVALÚA LAS SIGUIENTES POTENCIAS RECUERDA ESCRIBIR EL PROCEDIMIENTO. MIRA EL EJEMPLO 32 = 3• 3 = 9 a) 53 = b) 34 = c) x* . x6 = d) a12. at = e) 5-8. 53= f) (4* )2 g) (3?)2. Il- HALLA LAS RAICES CUADRADAS Y CUBICAS SEGÚN SE SOLICITE CONTESTARÁS COMO EN ESTE EJEMPLO: J4 = 2 (porque 22 = 2 x 2 = 4) 27 V9 = श = V16 = %3D V25 = %3D 36 = 49 125 %3D V64 = 343 81= 216 100 = 121 %3D 512 %3D 144 %3D 169 =
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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evaluate the following powers, write the procedure
![I- EVALÚA LAS SIGUIENTES POTENCIAS RECUERDA ESCRIBIR EL PROCEDIMIENTO. MIRA EL EJEMPLO
32 = 3• 3 = 9
a) 53 =
b) 34 =
c) x* . x6 =
d) a12. at =
e) 5-8. 53=
f) (4ª)2,
g) (32)2_
Il- HALLA LAS RAICES CUADRADAS Y CUBICAS SEGÚN SE SOLICITE CONTESTARÁS COMO EN ESTE EJEMPLO:
J 4 = 2
(porque 22 = 2 x 2 = 4)
27
64 =
V16 =
V25 =
%3D
36 =
125
%3D
49
%3D
V64 =
343
81=
216
100 =
121
/512
%3D
%3D
144
%3D
169 =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0fcdf7a1-5aa2-412b-b80a-42bc510e8c05%2F86955609-84c1-4b23-9989-c4dfc8f02597%2Fxlk5kci_processed.jpeg&w=3840&q=75)
Transcribed Image Text:I- EVALÚA LAS SIGUIENTES POTENCIAS RECUERDA ESCRIBIR EL PROCEDIMIENTO. MIRA EL EJEMPLO
32 = 3• 3 = 9
a) 53 =
b) 34 =
c) x* . x6 =
d) a12. at =
e) 5-8. 53=
f) (4ª)2,
g) (32)2_
Il- HALLA LAS RAICES CUADRADAS Y CUBICAS SEGÚN SE SOLICITE CONTESTARÁS COMO EN ESTE EJEMPLO:
J 4 = 2
(porque 22 = 2 x 2 = 4)
27
64 =
V16 =
V25 =
%3D
36 =
125
%3D
49
%3D
V64 =
343
81=
216
100 =
121
/512
%3D
%3D
144
%3D
169 =
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