N goNSU | Northeastern State Univ x* OWLV2 | Online teaching and lea Xb My Questions | bartlebyContentA east.cengagenow.com/ilrn/takeAssignment/takeCovalentActivity.do?locator=assignment-takeChapter 6 Homework - EOC[References]Calculate AH for the reaction:Question 51 ptQuestion 61 pt2NH3 (9) + 02 (g) → N¿H4 (1) + H20(1)Question 7O 1 ptgiven the following data:Question 81 pt2NH3 (9) + 3N20(g) + 4N2 (9) + 3H2O(1) AH = -1010. kJO 1 ptN20(g) + 3H2 (g)+ N2H4 (1) + H2O(1) AH = -317 kJQuestion 9N2H4 (1) + O2 (9) → N2(g) + 2H,0(1)AH = -623 kJQuestion 10 O1 ptH2 (9) + O2(9)+ H2O(1)AH = -286 kJQuestion 111 ptQuestion 12 O 1 ptΔΗ-kJNumeric input fieldQuestion 131 ptSubmit AnswerTry Another Version3 item attempts remainingQuestion 141 ptQuestion 151 ptQuestion 161 ptQuestion 171 ptQuestion 18 O 1 ptQuestion 191 ptQuestion 201 ptProgress:12/20 itemsDue Mar 30 at(PreviousNext11:55 PM9:37 PMP Type here to searchHiaG 4x ENG99+3/29/202120 N goNSU | Northeastern State Univ x* OWLV2 | Online teaching and lear Xb My Questions | bartlebyx +ContentA east.cengagenow.com/ilrn/takeAssignment/takeCovalentActivity.do?locator=assignment-takeChapter 6 Homework - EOC[References)Question 5O 1 ptGiven the following dataC2H4 (9) + 302(g) → 2 CO2(9) + 2H20(1)2C2 Hs (g) + 702 (9) → 4 CO2(g) + 6H2O(1)2H2 (g) + O2 (9) → 2H2O(1)Question 61 ptAH= -1411.0 kJAH=-3119.8 kJQuestion 7O 1 ptAH=-571.7 kJQuestion 81 ptcalculate A H for the reactionQuestion 9O 1 ptC2H4 (9) + H2 (g) → C,H6 (g)Question 10 O 1 ptΔΗ=kJQuestion 11O 1 ptQuestion 12 O 1 ptSubmit AnswerTry Another Version2 item attempts remainingQuestion 131 ptQuestion 141 ptQuestion 151 ptQuestion 161 ptQuestion 17 1 ptQuestion 18 O 1 ptQuestion 191 ptQuestion 201 ptProgress:12/20 itemsDue Mar 30 at(PreviousNext11:55 PM9:36 PMP Type here to searchHia99+G 1x ENG203/29/2021

i east.cengagenow.com/ilrn/takeAssignment/takeCovalentActivity.do?locator=assignment-take Chapter 6 Homework - EOC [References) Question 5 1 pt Given the following data C,H« (9) + 302(9) →2CO2(9) + 2H2O(1) 2C,H (9) + 702(9) →4CO2(9) + 6H2O(1) AH=-3119.8 kJ 2H2 (9) + O2(9) → 2H2O(1) Question 6 O 1 pt AH= -1411.0 kJ Question 7 O 1 pt AH=-571.7 kJ Question 8 1 pt calculate AH for the reaction Question 9 O 1 pt C,H. (9) + H2 (9) → C,He (9) Question 10 O 1 pt AH= kJ Question 11 O 1 pt Question 12 8 1 pt Submit Answer Try Another Version 2 item attempts remaining Question 13 1 pt Question 14 1 pt Question 15 1 pt Question 16 1 pt Question 17 O 1 pt Question 18 O 1 pt Question 19 1 pt Question 20 1 pt

i east.cengagenow.com/ilrn/takeAssignment/takeCovalentActivity.do?locator=assignment-take Chapter 6 Homework - EOC [References) Question 5 1 pt Given the following data C,H« (9) + 302(9) →2CO2(9) + 2H2O(1) 2C,H (9) + 702(9) →4CO2(9) + 6H2O(1) AH=-3119.8 kJ 2H2 (9) + O2(9) → 2H2O(1) Question 6 O 1 pt AH= -1411.0 kJ Question 7 O 1 pt AH=-571.7 kJ Question 8 1 pt calculate AH for the reaction Question 9 O 1 pt C,H. (9) + H2 (9) → C,He (9) Question 10 O 1 pt AH= kJ Question 11 O 1 pt Question 12 8 1 pt Submit Answer Try Another Version 2 item attempts remaining Question 13 1 pt Question 14 1 pt Question 15 1 pt Question 16 1 pt Question 17 O 1 pt Question 18 O 1 pt Question 19 1 pt Question 20 1 pt

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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pt pt 1 pt 8 https://east.cengagenow.com/ilmn/takeAssignment/takeCovalentActivity.do?locator assignment-take 1 pt Isomer #1: 1 pt Isomer #2: 1 pt [References] Provide the name(s) for the branched constitutional isomer(s) with the molecular formula C7H16 that have three methyl groups. If there is only a single isomer, leave the second space blank. Submit Answer er Chec Try Another Version C|Chec 2 item attempts remaining CI need C Draw C Draw > + v 7:33 PM 6/29/2022 0
1. Explain the differences between MgSO4 (s), M9SO4 (aq), and MgSO4 • 7 H2O (s). mique,
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OWLv2 Online tea x Search Results | Co x Paraphrasing Toal x enow.com/ilrn/takeAssignmenit/takeCovalentActivity.dolocatorassignment-take I Activity Log - USTA M Inbox - patrickcent. EMISTRY References] Use the References to access iimportant values if needed for tthis qu Consider the following half-reactioans: Half reaction E V) F2(g + 2e 2F (aq) 2.870V Cu"taq) + 2e Cu(s) 0.337V AF(ag) + 3e Al(s) -1.660 V (1) The weakest ozidizang agent is enter formula (2) The strongest reducing agent is (3) The strongest oxidizang agent is (4) The weakest reducing agent (5) Will F (aq) reduce AF (aq) to Al(s)? (6) Which species can be oxadized by Cu (ag)? If none, leave box blank Submit Answer Try Another Version 3 term attempts remaning Cengage Learming Cengage "echical Support
8. Calculate AG in two different ways for thecombustion of benzene: 2 C6H6 (1) + 15 02 (g) -12 CO2 (g) + 6 H20 (1) Are the two values equal?
PRE-LAB ASSIGNMENT 1. What is the concentration of Ca2+ in ppm if [Ca2*] is 3.85 x 105 M? 2. Why is it important to prepare CaF2(aq) solutions in polypropylene bottles rather than using glass bottles? How would this affect the measurement of F concentration? Include chemical reaction(s) to support your answer.
47. The maximum safe [Pb2+]=4.8x10-8M. Maintaining 1.0x10-4M levels for one of the anions below could ensure that this level is achieved by (Ksp of PbF2=3.6x10-8, PbCl2=1.7x10-5, PbCO3=7.4x10-14, and PbSO4=6.3x10-7) a. fluoridation b. chlorination c. adding sulfates d. carbonation
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B PLQ454 - CHM131A-N808: In x B CHM131-N808: Introduction X OWLV2 | Online teaching and x now.com/ilrn/takeAssignment/takeCovalentActivity.do?locator=Dassignment-take and Equilibrium [References] [Fe]=0.0 M [SCN]=0.0 M [FESCN21=0.0040 M Run the simulation again. Because Fe and SCN start with the same concentration, their lines overlap on the graph. What is the ratio of concentrations at equilibrium? FESCN*] Fe| [SCN|]| Recheck Nex (2 of 3) 5th attempt Incorrect The ratio of equilibrium concentrations for this trial is FESCN] [Fe ][SCN] (2.85 × 10*)(2.85×10*) (1.15x108) Submit Answer Try Another Version 10 item attempts remaining rch DELL
Stability constants CdOH+; log B₁ = 3.9 Cd(OH)2°; log B₂ = 7.6 CdSO4°; log B₁ = 2.3 Cd(SO4)22; log ẞ₂ = 3.2 Cd(SO4)3; log ẞ3 = 2.7 Free ligand concentrations (moles/kg) [OH‍]Ƒ= 10-5.9 F [CO3²] F = 10-5.4 CdC1+; log B₁ = 2.0 CdCl2°; log ẞ2 = 2.6 CdC13; log ẞ3 = 2.4 CdC14²; log ẞ4 = 1.7 [SO4²] F = 10-4.0 [Cl‍] = 10-3.7