A solution is prepared by adding 0.19 mole of Ni(NH3), Cl2 to 0.50 L of 3.9 M NH3. Calculate Ni (NH3),*| and Ni?+ for Ni (NH3),+ is 5.5 x 10$. That is, in this solution. Koverall Ni(NH,), [N²-] INH" 5.5 x 108 = for the overall reaction Ni2+ (ag) + 6NH3 (aq) = Ni(NH3),* (ag) [NI(NH,),]-C 2+ M [N*]-C M 3 item attempts remaining Submit Answer Try Another Version
A solution is prepared by adding 0.19 mole of Ni(NH3), Cl2 to 0.50 L of 3.9 M NH3. Calculate Ni (NH3),*| and Ni?+ for Ni (NH3),+ is 5.5 x 10$. That is, in this solution. Koverall Ni(NH,), [N²-] INH" 5.5 x 108 = for the overall reaction Ni2+ (ag) + 6NH3 (aq) = Ni(NH3),* (ag) [NI(NH,),]-C 2+ M [N*]-C M 3 item attempts remaining Submit Answer Try Another Version
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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[References]
A solution is prepared by adding 0.19 mole of Ni(NH3). Cl2 to 0.50 L of 3.9 M NH3. Calculate Ni (NH3),* and Ni²+
in this solution. Koverall
for Ni (NH3)+ is 5.5 x 10°. That is,
[NI(NH,),
2+
5.5 x 108 =
for the overall reaction
Ni?+ (aq) + 6NH3 (aq) = Ni(NH3)6* (ag)
%3D
[N*] =[
M
Try Another Version
3 item attempts remaining
Submit Answer
4:44 PM
3/30/20
search
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Transcribed Image Text:w.com/ilrn/takeAssignment/takeCovalentActivity.do?locator=assignment-take
[References]
A solution is prepared by adding 0.19 mole of Ni(NH3). Cl2 to 0.50 L of 3.9 M NH3. Calculate Ni (NH3),* and Ni²+
in this solution. Koverall
for Ni (NH3)+ is 5.5 x 10°. That is,
[NI(NH,),
2+
5.5 x 108 =
for the overall reaction
Ni?+ (aq) + 6NH3 (aq) = Ni(NH3)6* (ag)
%3D
[N*] =[
M
Try Another Version
3 item attempts remaining
Submit Answer
4:44 PM
3/30/20
search
远
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