2. For each of the following pair of reactions, CIRCLE the reaction that will occur faster (A or B).

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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please explain each choice.

### Reaction Rate Comparison for Each Pair of Reactions

For each of the following pairs of reactions, circle the reaction that will occur faster (A or B):

#### First Pair of Reactions:

**Reaction A:**
- **Reactant:** Cyclohexane derivative with a bromine substituent (Br) at the equatorial position and tert-butyl group at the axial position.
- **Reagent:** CH₃ONa in CH₃OH (methanol)
- **Reaction Condition:** 

**Reaction B:**
- **Reactant:** Cyclohexane derivative with a bromine substituent (Br) at the axial position and tert-butyl group at the axial position.
- **Reagent:** CH₃ONa in CH₃OH (methanol)
- **Reaction Condition:**

**Graph Explanation:** The reactions involve nucleophilic substitution, and the rate can depend on the position of the leaving group (bromine). 

#### Second Pair of Reactions:

**Reaction A:**
- **Reactant:** (R)-2-Iodopropane
- **Reagent:** NaCN in ACN (acetonitrile)
- **Reaction Condition:**

**Reaction B:**
- **Reactant:** (S)-2-Chloropropane
- **Reagent:** NaCN in ACN (acetonitrile)
- **Reaction Condition:**

**Graph Explanation:** The reactions involve nucleophilic substitution, where the leaving group (iodine vs. chlorine) will influence the rate of reaction due to their differing leaving group abilities.

#### Third Pair of Reactions:

**Reaction A:**
- **Reactant:** 1-Bromo-2-methylpropane
- **Reagent:** NaI in DMSO (dimethyl sulfoxide)
- **Reaction Condition:**

**Reaction B:**
- **Reactant:** 2-Bromo-2-methylpropane
- **Reagent:** NaI in DMSO (dimethyl sulfoxide)
- **Reaction Condition:**

**Graph Explanation:** The reactions involve nucleophilic substitution, and the position of the leaving group (primary vs. secondary carbon) affects steric hindrance and thus the reaction rate.

To determine which reactions will occur faster, consider the factors influencing nucleophilic substitution reactions, such as the nature of the leaving group, steric accessibility, and the type of nucleophile and solvent used.
Transcribed Image Text:### Reaction Rate Comparison for Each Pair of Reactions For each of the following pairs of reactions, circle the reaction that will occur faster (A or B): #### First Pair of Reactions: **Reaction A:** - **Reactant:** Cyclohexane derivative with a bromine substituent (Br) at the equatorial position and tert-butyl group at the axial position. - **Reagent:** CH₃ONa in CH₃OH (methanol) - **Reaction Condition:** **Reaction B:** - **Reactant:** Cyclohexane derivative with a bromine substituent (Br) at the axial position and tert-butyl group at the axial position. - **Reagent:** CH₃ONa in CH₃OH (methanol) - **Reaction Condition:** **Graph Explanation:** The reactions involve nucleophilic substitution, and the rate can depend on the position of the leaving group (bromine). #### Second Pair of Reactions: **Reaction A:** - **Reactant:** (R)-2-Iodopropane - **Reagent:** NaCN in ACN (acetonitrile) - **Reaction Condition:** **Reaction B:** - **Reactant:** (S)-2-Chloropropane - **Reagent:** NaCN in ACN (acetonitrile) - **Reaction Condition:** **Graph Explanation:** The reactions involve nucleophilic substitution, where the leaving group (iodine vs. chlorine) will influence the rate of reaction due to their differing leaving group abilities. #### Third Pair of Reactions: **Reaction A:** - **Reactant:** 1-Bromo-2-methylpropane - **Reagent:** NaI in DMSO (dimethyl sulfoxide) - **Reaction Condition:** **Reaction B:** - **Reactant:** 2-Bromo-2-methylpropane - **Reagent:** NaI in DMSO (dimethyl sulfoxide) - **Reaction Condition:** **Graph Explanation:** The reactions involve nucleophilic substitution, and the position of the leaving group (primary vs. secondary carbon) affects steric hindrance and thus the reaction rate. To determine which reactions will occur faster, consider the factors influencing nucleophilic substitution reactions, such as the nature of the leaving group, steric accessibility, and the type of nucleophile and solvent used.
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i dont understand the explanations, im still a bit confused as to why it is not b, b, a

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