Two discrete random variables X and Y have joint probability mass function (pmf) ‚n;_y=1,2, x. f(x) = بر k x = 1, 2, n(n+1) 0 otherwise (d) Use the fact that E(Y) = Ex (Ey|x (YX)), where Ex() and Exx() are the expected values with respect to X and with respect to Y given X, respectively, n(n+3) to show that E(Y) 4 =

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9.
Two discrete random variables X and Y have joint probability mass function
(pmf)
f(x) =
k x = 1,2,
n(n+1)
otherwise
{
=
0
1,2,...,n; y = 1,2, x.
·
(d)
Use the fact that E(Y) = Ex (Ey\x(Y|X)), where Ex( ) and Ey|x ( ) are the
expected values with respect to X and with respect to Y given X, respectively,
n(n+3)
to show that E(Y)
4
Transcribed Image Text:9. Two discrete random variables X and Y have joint probability mass function (pmf) f(x) = k x = 1,2, n(n+1) otherwise { = 0 1,2,...,n; y = 1,2, x. · (d) Use the fact that E(Y) = Ex (Ey\x(Y|X)), where Ex( ) and Ey|x ( ) are the expected values with respect to X and with respect to Y given X, respectively, n(n+3) to show that E(Y) 4
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Hi!

I don't understand how 4(n+1)/(n-1) matches n(n+3)/4.

They are not equal as far as I can see or understand. Is there an error in the solution or am I missing something?

Brgds

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