I don't really get why the force shouldn't be in those directions and the reverse is not true either so I'm at a loss if you could explan this to me it would really help Let a uniform magnetic field B define the +z-direction. A charged point particle enters the magnetic field withvelocity v = (Ux, Uy, U₂).For different values of the velocity components Ux, Uy, and U₂, categorize the particle's motion as linear, circular, or helical.Assume that all nonzero velocity components are greater than zero.ncelinear(0, 0, V₂)(Ux, 0, 0)(0, v₂, 0)circular(Vx, 0, Uz)(0, Uy, Uz)(Vx, Vy, 0)Answer Bankhelical(Ux, Uy, Uz)

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College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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I don't really get why the force shouldn't be in those directions and the reverse is not true either so I'm at a loss if you could explan this to me it would really help

Let a uniform magnetic field B define the +z-direction. A charged point particle enters the magnetic field with
velocity v = (Ux, Uy, U₂).
For different values of the velocity components Ux, Uy, and U₂, categorize the particle's motion as linear, circular, or helical.
Assume that all nonzero velocity components are greater than zero.
nce
linear
(0, 0, V₂)
(Ux, 0, 0)
(0, v₂, 0)
circular
(Vx, 0, Uz)
(0, Uy, Uz)
(Vx, Vy, 0)
Answer Bank
helical
(Ux, Uy, Uz)

Expert Solution

Step 1: Magnetic force expression

The magnetic force acting on a charged particle in a magnetic field is given as:

$F with rightwards arrow on top equals q left parenthesis v with rightwards arrow on top cross times B with rightwards arrow on top right parenthesis$

Where:

$q$ is the charge of the particle.
$v with rightwards arrow on top$ is the velocity of the particle.
$B with rightwards arrow on top$ is the magnetic field.

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