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I did all steps just need help figuring out “The ball’s velocity at the above time is”

I did all steps just need help figuring out “The ball’s velocity at the above time is”

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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I did all steps just need help figuring out “The ball’s velocity at the above time is”
Determine the acceleration function of the ball. a(t) -9.8 o Determine the time required for the ball to reach its maximum height, the maximum height of the ball, and the ball's velocity and acceleration at that height. Round solutions to the nearest thousandth, if necessary. The ball reaches a maximum height after 1.531 vo seconds. The ball reaches a maximum height of 261.47959183 vo meters The ball's velocity at the above height is meters per second The ball's acceleration at the above height is-9.8 o meters per second squared v Determine the time required for the ball to reach ground level and the ball's velocity and acceleration at that time. Round solutions to the nearest thousandth, if necessary. The ball reaches ground level after 8.836 seconds. The ball's velocity at the above time is meters per second The ball's acceleration at the above time is -9.8 o meters per second squared v Question Help: Message instructor Submit All Parts
Transcribed Image Text:Determine the acceleration function of the ball. a(t) -9.8 o Determine the time required for the ball to reach its maximum height, the maximum height of the ball, and the ball's velocity and acceleration at that height. Round solutions to the nearest thousandth, if necessary. The ball reaches a maximum height after 1.531 vo seconds. The ball reaches a maximum height of 261.47959183 vo meters The ball's velocity at the above height is meters per second The ball's acceleration at the above height is-9.8 o meters per second squared v Determine the time required for the ball to reach ground level and the ball's velocity and acceleration at that time. Round solutions to the nearest thousandth, if necessary. The ball reaches ground level after 8.836 seconds. The ball's velocity at the above time is meters per second The ball's acceleration at the above time is -9.8 o meters per second squared v Question Help: Message instructor Submit All Parts
The position of a free-falling object is given by 8(t) = - 4.9t + vot + 80 where s(t) is measured in meters, vo represents the initial velocity of the object, and so represents the initial position of the object. A ball is thrown vertically upward with a velocity of 15 meters per second, off of a building that is 250 meters tall. Use the above position function to address the following prompts. Determine the position function of the ball. s(t) = -4.9t2 + 15t + 250 v Determine the velocity function of the ball. v(t) = -9.8t + 15 vo Determine the acceleration function of the ball. a(t) = -9.8. Determine the time required for the ball to reach its maximum height, the maximum height of the ball, and the ball's velocity and acceleration at that height. Round solutions to the nearest thousandth, if necessary. The ball reaches a maximum height after 1.531 v o seconds. The ball reaches a maximum height of 261.47959183 meters The ball's velocity at the above height is 0 meters per second The ball's acceleration at the above height is-9.8 o meters per second squared v Determine the time required for the ball to reach ground level and the ball's velocity and acceleration at that time. Round solutions to the nearest thousandth, if necessary.
Transcribed Image Text:The position of a free-falling object is given by 8(t) = - 4.9t + vot + 80 where s(t) is measured in meters, vo represents the initial velocity of the object, and so represents the initial position of the object. A ball is thrown vertically upward with a velocity of 15 meters per second, off of a building that is 250 meters tall. Use the above position function to address the following prompts. Determine the position function of the ball. s(t) = -4.9t2 + 15t + 250 v Determine the velocity function of the ball. v(t) = -9.8t + 15 vo Determine the acceleration function of the ball. a(t) = -9.8. Determine the time required for the ball to reach its maximum height, the maximum height of the ball, and the ball's velocity and acceleration at that height. Round solutions to the nearest thousandth, if necessary. The ball reaches a maximum height after 1.531 v o seconds. The ball reaches a maximum height of 261.47959183 meters The ball's velocity at the above height is 0 meters per second The ball's acceleration at the above height is-9.8 o meters per second squared v Determine the time required for the ball to reach ground level and the ball's velocity and acceleration at that time. Round solutions to the nearest thousandth, if necessary.
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