И Block 2 Ф м т A V, -х м м |Block 1

icon
Related questions
Question

Two blocks slide on a collision course across a frictionless surface, as in the figure. The resulting collision is inelastic. The first block has mass M = 1.00 kg and is initially sliding due north at a speed of Vi = 8.75 m/s.The second block has mass m = 7.20 ✕ 10−2 kg and is initially sliding at a speed of vi = 13.5 m/s directed at an angleθ = 29.5° south of east. Immediately after the inelastic collision, the second block is observed sliding at vf = 5.15 m/s in a direction ofϕ = 17.5°north of east.

 

Determine the components of the first block's velocity after the collision.


Vxf  =    m/s
Vyf  =    m/s

 

И
Block 2
Ф
м
т
A V,
-х
м
м |Block 1
Transcribed Image Text:И Block 2 Ф м т A V, -х м м |Block 1
Expert Solution
steps

Step by step

Solved in 4 steps with 4 images

Blurred answer
Similar questions
  • SEE MORE QUESTIONS