И Block 2 Ф м т A V, -х м м |Block 1
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Two blocks slide on a collision course across a frictionless surface, as in the figure. The resulting collision is inelastic. The first block has mass M = 1.00 kg and is initially sliding due north at a speed of Vi = 8.75 m/s.The second block has mass m = 7.20 ✕ 10−2 kg and is initially sliding at a speed of vi = 13.5 m/s directed at an angleθ = 29.5° south of east. Immediately after the inelastic collision, the second block is observed sliding at vf = 5.15 m/s in a direction ofϕ = 17.5°north of east.
Determine the components of the first block's velocity after the collision.
Vxf | = | m/s | |
Vyf | = | m/s |
![И
Block 2
Ф
м
т
A V,
-х
м
м |Block 1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3a6c74b5-6944-4f18-a9dd-bba2c0ef3fdd%2Fb00fd97f-6dee-48e3-9e2c-17f793e0ffe0%2Fqb959q.gif&w=3840&q=75)
Transcribed Image Text:И
Block 2
Ф
м
т
A V,
-х
м
м |Block 1
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