I am wondering how to do this problem: A mixing beater consists of three thin rods, each 10.4 cm long. The rods diverge from a central hub, separated from each other by 120°, and all turn in the same plane. A ball is attached to the end of each rod. Each ball has cross-sectional area 4.10 cm2 and is so shaped that it has a drag coefficient of 0.620. The drag force on each ball is R = (1/2) D ρ A v2 where D is the drag coefficient, ρ the density of the fluid, A the cross-sectional area, and v the speed of the object moving through the fluid. (a) Calculate the power input required to spin the beater at 1000 rev/min in water. (b) The beater is taken out of the water and held in air. If the input power remains the same (it wouldn't, but if it did), what would be the new rotation speed?
Rotational Equilibrium And Rotational Dynamics
In physics, the state of balance between the forces and the dynamics of motion is called the equilibrium state. The balance between various forces acting on a system in a rotational motion is called rotational equilibrium or rotational dynamics.
Equilibrium of Forces
The tension created on one body during push or pull is known as force.
I am wondering how to do this problem:
A mixing beater consists of three thin rods, each 10.4 cm long. The rods diverge from a central hub, separated from each other by 120°, and all turn in the same plane. A ball is attached to the end of each rod. Each ball has cross-sectional area 4.10 cm2 and is so shaped that it has a drag coefficient of 0.620. The drag force on each ball is
where D is the drag coefficient, ρ the density of the fluid, A the cross-sectional area, and v the speed of the object moving through the fluid.
(a) Calculate the power input required to spin the beater at 1000 rev/min in water.
(b) The beater is taken out of the water and held in air. If the input power remains the same (it wouldn't, but if it did), what would be the new rotation speed?
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