Hydrogen sulfide and oxygen react to form sulfur dioxide and water, like this: 2 H, S(9)+30,(9) → 2 SO,(9)+2H,O(9) Use this chemical equation to answer the questions in the table below. Suppose 75.0 mmol of H,S and O None. 113. mmol of 0, are added to an O Some, but less than 75.0 mmol. empty flask. How much SO, will be O 75.0 mmol. in the flask at equilibrium? O More than 75.0 mmol. Suppose 165. mmol of SO, and O None. 165. mmol of H,0 are added to an O Some, but less than 165. mmol. empty flask. How much SO, will be O 165. mmol. in the flask at equilibrium? O More than 165. mmol.
Hydrogen sulfide and oxygen react to form sulfur dioxide and water, like this: 2 H, S(9)+30,(9) → 2 SO,(9)+2H,O(9) Use this chemical equation to answer the questions in the table below. Suppose 75.0 mmol of H,S and O None. 113. mmol of 0, are added to an O Some, but less than 75.0 mmol. empty flask. How much SO, will be O 75.0 mmol. in the flask at equilibrium? O More than 75.0 mmol. Suppose 165. mmol of SO, and O None. 165. mmol of H,0 are added to an O Some, but less than 165. mmol. empty flask. How much SO, will be O 165. mmol. in the flask at equilibrium? O More than 165. mmol.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Hydrogen sulfide and oxygen react to form sulfur dioxide and water, like this:
2 H, S(9)+30,(9) → 2 SO,(9)+2H,O(9)
Use this chemical equation to answer the questions in the table below.
Suppose 75.0 mmol of H, S and
O None.
113. mmol of 0, are added to an
O Some, but less than 75.0 mmol.
empty flask. How much SO, will be
O 75.0 mmol.
in the flask at equilibrium?
O More than 75.0 mmol.
Suppose 165. mmol of SO,
and
O None.
165. mmol of H,0 are added to an
O Some, but less than 165. mmol.
empty flask. How much SO, will be
O 165. mmol.
in the flask at equilibrium?
O More than 165. mmol.
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