Hydrogen peroxide decomposes spontaneously to yield water and oxygen gas according to the reaction equation 2H2O2(aq)⟶2H2O(l)+O2(g)2H2O2(aq)⟶2H2O(l)+O2(g) The activation energy for this reaction is 75 kJ⋅mol−1.75 kJ⋅mol−1. The enzyme catalase, found in blood, lowers the activation energy to 8.0 kJ⋅mol−1.8.0 kJ⋅mol−1. At what temperature would the non‑catalyzed reaction need to be run to have a rate equal to that of the enzyme‑catalyzed reaction at 25 ∘C?
Hydrogen peroxide decomposes spontaneously to yield water and oxygen gas according to the reaction equation 2H2O2(aq)⟶2H2O(l)+O2(g)2H2O2(aq)⟶2H2O(l)+O2(g) The activation energy for this reaction is 75 kJ⋅mol−1.75 kJ⋅mol−1. The enzyme catalase, found in blood, lowers the activation energy to 8.0 kJ⋅mol−1.8.0 kJ⋅mol−1. At what temperature would the non‑catalyzed reaction need to be run to have a rate equal to that of the enzyme‑catalyzed reaction at 25 ∘C?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Hydrogen peroxide decomposes spontaneously to yield water and oxygen gas according to the reaction equation
2H2O2(aq)⟶2H2O(l)+O2(g)2H2O2(aq)⟶2H2O(l)+O2(g)
The activation energy for this reaction is 75 kJ⋅mol−1.75 kJ⋅mol−1. The enzyme catalase, found in blood, lowers the activation energy to 8.0 kJ⋅mol−1.8.0 kJ⋅mol−1.
At what temperature would the non‑catalyzed reaction need to be run to have a rate equal to that of the enzyme‑catalyzed reaction at 25 ∘C?
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