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Hydrazine, N2H4 , has been used as a rocket fuel because its reaction with oxygen is extremely exothermic: (a) N2H4(1) + O2(g) → N2(g) + 2H20(g) AH = – 534.0 kJ The enthalpy change for the vaporization of water is given by: (b) H2O(1)→ H2O(g) ΔΗ -40.7 kJ Calculate the enthalpy change that would result if the water were produced in liquid rather than the gaseous form. N2H4(0) + O2(g) → N2(g) + 2H2O{1) ΔΗ-?

Hydrazine, N2H4 , has been used as a rocket fuel because its reaction with oxygen is extremely exothermic: (a) N2H4(1) + O2(g) → N2(g) + 2H20(g) AH = – 534.0 kJ The enthalpy change for the vaporization of water is given by: (b) H2O(1)→ H2O(g) ΔΗ -40.7 kJ Calculate the enthalpy change that would result if the water were produced in liquid rather than the gaseous form. N2H4(0) + O2(g) → N2(g) + 2H2O{1) ΔΗ-?

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Hydrazine, N,H4 , has been used as a rocket fuel because its reaction with oxygen is extremely exothermic: (a) N2H40) + O2(g) → N2(g) + 2H2O(g) AH = – 534.0 kJ The enthalpy change for the vaporization of water is given by: (b) H2O1)→ H2O(8) AH = 40.7 kJ Calculate the enthalpy change that would result if the water were produced in liquid rather than the gaseous form. N2H4(1) + O2(g) → N2(g) + 2H2O(1) ΔΗ- (Round off answer to the second decimal place.)
Transcribed Image Text:Hydrazine, N,H4 , has been used as a rocket fuel because its reaction with oxygen is extremely exothermic: (a) N2H40) + O2(g) → N2(g) + 2H2O(g) AH = – 534.0 kJ The enthalpy change for the vaporization of water is given by: (b) H2O1)→ H2O(8) AH = 40.7 kJ Calculate the enthalpy change that would result if the water were produced in liquid rather than the gaseous form. N2H4(1) + O2(g) → N2(g) + 2H2O(1) ΔΗ- (Round off answer to the second decimal place.)
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