HW Score: 0%, O of 16 pts Question Help O The price-earnings ratios for all companies whose shares are traded on a specific stock exchange followa normal distribution with a standard deviston of 43 Arandom sample of these companies is selected in order to estimate the population mean price-earnings ratio Complete parts (a) through (c) a How large a sample is necessary in order to ensure that the probablity that the sample mean differs from the population mean by more than 1.1s less than 0 107 The sample size must be at least 42. (Type a whole number) b. Without doing the calculations, state whether a larger or smaller sample size compared to the sample sze in part (a) wouid be requred to gurantee that the probability of the sample mean differing from the population mean by more than 1.1 is less than 005. Inco The sample size would need to be

HW Score: 0%, O of 16 pts Question Help O The price-earnings ratios for all companies whose shares are traded on a specific stock exchange followa normal distribution with a standard deviston of 43 Arandom sample of these companies is selected in order to estimate the population mean price-earnings ratio Complete parts (a) through (c) a How large a sample is necessary in order to ensure that the probablity that the sample mean differs from the population mean by more than 1.1s less than 0 107 The sample size must be at least 42. (Type a whole number) b. Without doing the calculations, state whether a larger or smaller sample size compared to the sample sze in part (a) wouid be requred to gurantee that the probability of the sample mean differing from the population mean by more than 1.1 is less than 005. Inco The sample size would need to be

Name: HW Score: 0%, O of 16 ptsQuestion Help OThe price-earnings ratios for
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Description: HW Score: 0%, O of 16 ptsQuestion Help OThe price-earnings ratios for all companies whose shares are traded on a specific stock exchange followa normal distribution with a standard deviston of 43 Arandomsample of these companies is selected in order

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The weight distribution of parcels sent in a certain manner is normal with mean value 12 Ib and standard deviation 3.4 lb. The parcel service wishes to establish a weight value c peyond which there will be a surcharge. In USE SALT What value of c is such that 99% of all parcels are at least 1 lb under the surcharge weight? (Round your answer to four decimal places.) Ib You may need to use the appropriate table in the Appendix of Tables to answer this question.
We wish to test if there is a difference in the median weights for yellow and brown M&M's. A random sample of both types of M&M's is selected and weighed. The data was analyzed in Statdisk and with the following results. Total Num Values: 59 Rank Sum 1: Rank Sum 2: 829.5000 940.5000 780 Mean : St Dev: 65.49809 Test Statistic, z: 0.7557 Critical z: ±1.959962 Fail to Reject the Null Hypothesis Of these two choices (Wilcoxon signed-rank for matched pairs or Wilcoxon signed-rank for two independent samples) what type of test should have been conducted? What can be concluded? O The Wilcoxon signed-rank for matched pairs should have been conducted. There is insufficient evidence to conclude that there is a difference in the median weight of yellow and brown M&M's. The Wilcoxon signed-rank for matched pairs should have been conducted. There is sufficient evidence to conclude that there is a difference in the median weight of yellow and brown M&M's. The Wilcoxon rank-sum for two independent…
Methyl t-butyl ether (MTBE) is an organic water contaminant that often results from gasoline spills. The level of MTBE (in parts per billion) was measured for a sample of 12 well sites located near the ship channel during a recent spilI. The data are: 150, 376, 38, 12, 11, 134, 12, 251, 63, 8, 13, 107. (a) Find the sample mean and the sample standard deviation. (b) Construct and interpret a 91.85% and 98.15% confidence interval for the population mean by using the following equations: B, = x – t - - and By = x +t N sample N sample (c) Which confidence interval is wider and why?
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