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How would I go about drawing the mechanism that forms the two products on the right? which one would be the major and minor and why

How would I go about drawing the mechanism that forms the two products on the right? which one would be the major and minor and why

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How would I go about drawing the mechanism that forms the two products on the right? which one would be the major and minor and why
The image shows a chemical reaction involving the addition of hydrobromic acid (H-Br) to an alkene. ### Reaction Details: 1. **Reactant:** - The starting molecule is styrene, a compound with a vinyl group (a carbon-carbon double bond) attached to a benzene ring. 2. **Reagent:** - H-Br is added across the carbon-carbon double bond. 3. **Products:** - The reaction produces two compounds: - Product 1: 1-Bromo-1-phenylethane, where the bromine atom attaches to the carbon that was previously double-bonded. - Product 2: 1-Bromo-2-phenylethane, where the bromine atom attaches to the other carbon of the former double bond. ### Explanation of the Diagram: - The arrow indicates the direction of the chemical reaction from reactants to products. - The use of a plus sign shows that the reaction yields two different products, likely through a competing mechanism of Markovnikov and anti-Markovnikov addition. This reaction is an example of hydrohalogenation, where hydrobromic acid adds across the double bond of an alkene to form haloalkanes.
Transcribed Image Text:The image shows a chemical reaction involving the addition of hydrobromic acid (H-Br) to an alkene. ### Reaction Details: 1. **Reactant:** - The starting molecule is styrene, a compound with a vinyl group (a carbon-carbon double bond) attached to a benzene ring. 2. **Reagent:** - H-Br is added across the carbon-carbon double bond. 3. **Products:** - The reaction produces two compounds: - Product 1: 1-Bromo-1-phenylethane, where the bromine atom attaches to the carbon that was previously double-bonded. - Product 2: 1-Bromo-2-phenylethane, where the bromine atom attaches to the other carbon of the former double bond. ### Explanation of the Diagram: - The arrow indicates the direction of the chemical reaction from reactants to products. - The use of a plus sign shows that the reaction yields two different products, likely through a competing mechanism of Markovnikov and anti-Markovnikov addition. This reaction is an example of hydrohalogenation, where hydrobromic acid adds across the double bond of an alkene to form haloalkanes.
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