how would I change the code in order to get this answer of -1.15 and -7.85, using    python3 quadratic.py 1 9 9 for example getting the answer to round up to 2 decimal places anwer comes out as  The solutions are -1.1458980337503153 and -7.85410196624968 But it should be The solutions are -1.15 and -7.85 heres the code  import sys def main():     if len(sys.argv) == 4:         a = float(sys.argv[1])         b = float(sys.argv[2])         c = float(sys.argv[3])         d = (b ** 2) - (4 * a * c)         if d < 0 or a == 0:             print("There are no roots")         else:             root1 = (-b + d ** 0.5) / (2 * a)             root2 = (-b - d ** 0.5) / (2 * a)             print("The solutions are", root1, "and", root2)     else:         print("Please provide 3 numbers as command line arguments")

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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how would I change the code in order to get this answer of -1.15 and -7.85,

using    python3 quadratic.py 1 9 9 for example

getting the answer to round up to 2 decimal places

anwer comes out as 

  1. The solutions are -1.1458980337503153 and -7.85410196624968

But it should be The solutions are -1.15 and -7.85

heres the code 

import sys


def main():
    if len(sys.argv) == 4:
        a = float(sys.argv[1])
        b = float(sys.argv[2])
        c = float(sys.argv[3])
        d = (b ** 2) - (4 * a * c)

        if d < 0 or a == 0:
            print("There are no roots")
        else:
            root1 = (-b + d ** 0.5) / (2 * a)
            root2 = (-b - d ** 0.5) / (2 * a)
            print("The solutions are", root1, "and", root2)
    else:
        print("Please provide 3 numbers as command line arguments")

 

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