program must be solved by python anaconda. My variant number is ( 21 ) 1. Given a sequence of integers in the range from 0 to N. For each number in the sequence, find the number of its divisors. Number N = 5 + number of your variant.2. Given a sequence of integers 1N, 12N, 123N, 1234N, 1235N. Find the sum of the even digits in each number. Where N is the number of your variant.

Answered: 1. 2. Given a sequence of integers in…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

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Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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program must be solved by python anaconda. My variant number is ( 21 )

1. Given a sequence of integers in the range from 0 to N. For each number in the sequence, find the number of its divisors. Number N = 5 + number of your variant.

2. Given a sequence of integers 1N, 12N, 123N, 1234N, 1235N. Find the sum of the even digits in each number. Where N is the number of your variant.

Expert Solution

1. number of divisors

Python program:

def findDevisor(v):

for i in range(1, v+5):

c = 0

for j in range(1,i+1):

if(i%j==0):

c = c+1

print('Number of devisors of '+str(i)+': '+str(c))

findDevisor(21)

Output:

Number of devisors of 1: 1
Number of devisors of 2: 2
Number of devisors of 3: 2
Number of devisors of 4: 3
Number of devisors of 5: 2
Number of devisors of 6: 4
Number of devisors of 7: 2
Number of devisors of 8: 4
Number of devisors of 9: 3
Number of devisors of 10: 4
Number of devisors of 11: 2
Number of devisors of 12: 6
Number of devisors of 13: 2
Number of devisors of 14: 4
Number of devisors of 15: 4
Number of devisors of 16: 5
Number of devisors of 17: 2
Number of devisors of 18: 6
Number of devisors of 19: 2
Number of devisors of 20: 6
Number of devisors of 21: 4
Number of devisors of 22: 4
Number of devisors of 23: 2
Number of devisors of 24: 8
Number of devisors of 25: 3