College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
Related questions
Question
How was I1 and I2 calculated?
![Apply KVL in Loop-1, and we get;
ɛ1 – I,R1 – R2 (I, + I2) = 0;
6 – 1000 x I, – 800 (I + I2) = 0;
91, + 412 = 3 x 10-2;
91, + 412 = 30 mA
9I, + 412 = 30 mA
(1)
Apply KVL in Loop-2, and we get;
€2 – R2 (Ij + I2) – I;R3;
12 – 800 (I1 + I2) – 70012 = 0 ;
81, + 1512 = 12 x 10-2;
81, + 1512 = 120 mA
(2)
After the solution of the equation (1) and (2), we get;
I = -0. 29 mA;
I2 = 8. 15 mA;
Iz = I, + 12 = –0. 29 + 8. 15
I3 = 7. 86 mA
Answer: I =
-0. 29 mA; I2 = 8. 15 mA; I3 = 7.86 mA.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa935d962-5701-4fdd-982b-a33835b6213e%2F9e6b595d-312f-4ace-9e13-3f61fa1374fa%2F3zgedze_processed.png&w=3840&q=75)
Transcribed Image Text:Apply KVL in Loop-1, and we get;
ɛ1 – I,R1 – R2 (I, + I2) = 0;
6 – 1000 x I, – 800 (I + I2) = 0;
91, + 412 = 3 x 10-2;
91, + 412 = 30 mA
9I, + 412 = 30 mA
(1)
Apply KVL in Loop-2, and we get;
€2 – R2 (Ij + I2) – I;R3;
12 – 800 (I1 + I2) – 70012 = 0 ;
81, + 1512 = 12 x 10-2;
81, + 1512 = 120 mA
(2)
After the solution of the equation (1) and (2), we get;
I = -0. 29 mA;
I2 = 8. 15 mA;
Iz = I, + 12 = –0. 29 + 8. 15
I3 = 7. 86 mA
Answer: I =
-0. 29 mA; I2 = 8. 15 mA; I3 = 7.86 mA.
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