1. 2. The parallel plates of an air capacitor are separated by 2.25 mm. Each plate carries a charge of 6.50 nC. The magnitude of the electric field of the plates is 4.75×105 V/m. Find the nises (a) potential difference between the plates, (b) capacitance, and (c) area of a plate. The relative permittivity of a dielectric is 2.25. (a) What is its permittivity? (b) What will be to the capacitance if this dielectric is inserted into a 7.8 μF air capacitor? tot lqqs eqidenoizalon

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2.
1.
The parallel plates of an air capacitor are separated by 2.25 mm. Each plate carries a charge of
6.50 nC. The magnitude of the electric field of the plates is 4.75×10' V/m. Find the
(a) potential difference between the plates, (b) capacitance, and (c) area of a plate.
O
res
The relative permittivity of a dielectric is 2.25. (a) What is its permittivity? (b) What will be to
the capacitance if this dielectric is inserted into a 7.8 μF air capacitor?qs tot vlqqs eqidencials
npa oboboi
Transcribed Image Text:2. 1. The parallel plates of an air capacitor are separated by 2.25 mm. Each plate carries a charge of 6.50 nC. The magnitude of the electric field of the plates is 4.75×10' V/m. Find the (a) potential difference between the plates, (b) capacitance, and (c) area of a plate. O res The relative permittivity of a dielectric is 2.25. (a) What is its permittivity? (b) What will be to the capacitance if this dielectric is inserted into a 7.8 μF air capacitor?qs tot vlqqs eqidencials npa oboboi
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