How to solve for freezing point depression given 10.3 g of glucose dissolved in 250 g? 1. What is the boiling point of a solution prepared by dissolving 2.50 g of biphenyl (C12 H10) n85.0 g of benzene? The molecular weight of biphenyl is 154 g.2. A solution contains of 10.3 g of glucose (C6 H1206) dissolved in 250 g of water. What is thefreezing point depression of the solvent?Activity 3: Choose the letter of the best answer:1. The boiling point elevation and freezing point depression depends on theA. concentration of solution and solvent usedB. concentration of solvent usedC. concentration of solute usedD. concentration of solution2. The presence of non-volatile solute in a solution,the boiling temperature.A.decreasesC.increasesB. does not affectD. changesTwo examples of colligative properties are boiling point and freezing point: due to the additions, the boiling point tends to increase, and freezing point tends toC. doubledD. remains constantB. increaseation when 147 g of lactic acid (C6 H 100 s) is dissolved in 647 g ofint constant for cyclohexane is 2.79 °C/m.tion of urea in this solvent

Given, Mass of glucose = 10.3 g Mass of water = 250 g Kf = 1.86 oC/m (from literature available on…

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How to solve for freezing point depression given 10.3 g of glucose dissolved in 250 g

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter11: Properties Of Solutions

Section: Chapter Questions

Problem 132CP: A forensic chemist is given a white solid that is suspected of being pure cocaine (C17H21NO4, molar...

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