How to I write a C++ program to get the numerical solution for the following problem using implicit scheme and SOR iteration?

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How to I write a C++ program to get the numerical solution for the following problem
using implicit scheme and SOR iteration?
Consider 10 diffusion equation be given as
du J²u
Ət əx²
0≤x≤ 2,0 ≤ t ≤ 10
Subject to the initial condition
u(x,0) = sin(x), 0 ≤ x ≤2
And the boundary conditions
u(0, t) = 0
0 ≤t≤ 10
The exact solution is given by
u(x, t) = e) sin(7), 0≤x≤ 2,0 ≤ t ≤ 10
Left
Condition
Inicial condition
to
right Condition
x
Transcribed Image Text:How to I write a C++ program to get the numerical solution for the following problem using implicit scheme and SOR iteration? Consider 10 diffusion equation be given as du J²u Ət əx² 0≤x≤ 2,0 ≤ t ≤ 10 Subject to the initial condition u(x,0) = sin(x), 0 ≤ x ≤2 And the boundary conditions u(0, t) = 0 0 ≤t≤ 10 The exact solution is given by u(x, t) = e) sin(7), 0≤x≤ 2,0 ≤ t ≤ 10 Left Condition Inicial condition to right Condition x
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Hi, can you re-write the ones I circled yellow? I couldn't really read it

11:10)
#include <stdio.k>11***
#include <math. ka
#
define X2
Main ()
float x [x] [x+1], a[x], ae max, t, s, e;
iuti, S
9
MXIE;
for(i=0; i< x; i++) a[i]=0;
puto ("Enter the elements of augmented
matrix rowwise");
for(j=0; j<x+1; j++)
{
Scauf ("1. f", & x[][j]);
3
3
Printf ("Enter to allowed enor and Naximu
& itention:");
number
G
Scauf("%. 6.%.d", & ae, & mx12);
Printf ("Itectionx [] x [2] ");
for (x=1) 92 = MXIE; 9 ++)
३
Max = 0;
for (i=0; i < x; i++)
e
8
0;
for (i=0; i < x; j++)
Teordne
[JJ;
1 (j=i) s += x [] []*
+=(x [] [x]-s1x BJDJ;
C
X
e fabs (a[i]. £);
a[i] = t;
[*] *10*7*
}
Tintf ("1. 5d", (a); (+47:30-11
fa li=0; i<x i++)
Printf (" (9.46, a BJ);
Фліна в (""");
ів (махкае).
(DAX
{
Printf ("Converse in /. 3oliteotion"
a) bur
196/2
>
for (i=0; i<xi++)
a
return 0
}
[7.30 ]=-1.7.46
i+1, a[i]).
Hung
**** (*=*) 10)
Transcribed Image Text:11:10) #include <stdio.k>11*** #include <math. ka # define X2 Main () float x [x] [x+1], a[x], ae max, t, s, e; iuti, S 9 MXIE; for(i=0; i< x; i++) a[i]=0; puto ("Enter the elements of augmented matrix rowwise"); for(j=0; j<x+1; j++) { Scauf ("1. f", & x[][j]); 3 3 Printf ("Enter to allowed enor and Naximu & itention:"); number G Scauf("%. 6.%.d", & ae, & mx12); Printf ("Itectionx [] x [2] "); for (x=1) 92 = MXIE; 9 ++) ३ Max = 0; for (i=0; i < x; i++) e 8 0; for (i=0; i < x; j++) Teordne [JJ; 1 (j=i) s += x [] []* +=(x [] [x]-s1x BJDJ; C X e fabs (a[i]. £); a[i] = t; [*] *10*7* } Tintf ("1. 5d", (a); (+47:30-11 fa li=0; i<x i++) Printf (" (9.46, a BJ); Фліна в ("""); ів (махкае). (DAX { Printf ("Converse in /. 3oliteotion" a) bur 196/2 > for (i=0; i<xi++) a return 0 } [7.30 ]=-1.7.46 i+1, a[i]). Hung **** (*=*) 10)
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