how to get "ivalid input" in my output i already have a code for this. def menu():

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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hi can u help me here i dont know how to get "ivalid input" in my output i already have a code for this.

def menu():
    flag = True
    while (flag):
        print("1. Addition")
        print("2. Subraction")
        print("3. Multiplication")
        print("4. Division")

        try:
            choice = int(input("Choose an operation: "))
            # ask user two numbers to perform the selected operation
            a = float(input("Enter first number: "))
            b = float(input("Enter second number: "))

            if choice == 1:
                result = a + b
            elif choice == 2:
                result = a - b
            elif choice == 3:
                result = a * b
            elif choice == 4:
                result = a / b
            else:
                print("Invalid Choice")

        except ZeroDivisionError:
            print("Cannot divide by zero")
            result = 0

        except ValueError:
            print("Please enter a numeric value")

        print("Result: ", result)

        i = int(input("Type 0 to continue else 1 to exit: "))
        if i == 0:
            flag = True
        else:
            flag = False


menu()

 

all i need is output that show "invalid input" 

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