How to fix this error in pgadmin 4 ===================================== ERROR: syntax error at or near ""students"" LINE 121: DROP "students"; ^ SQL state: 42601 Character: 4630 ==================================================================================   CREATE TABLE "courses"(    "courseId" SERIAL,    "courseName" VARCHAR(120) NOT NULL,     CONSTRAINT "courses_pk" PRIMARY KEY ("courseId") ); CREATE TABLE "students"(    "studentId" SERIAL,    "courseId" INT NOT NULL,    "studentName" VARCHAR(120) NOT NULL,    "studentEmail" VARCHAR(120) UNIQUE NOT NULL,    "studentPhone" INT NOT NULL,     CONSTRAINT "students_pk" PRIMARY KEY ("studentId"),     CONSTRAINT "courses_students_fk" FOREIGN KEY("courseId")       REFERENCES "courses"("courseId")       ON UPDATE NO ACTION       ON DELETE NO ACTION       NOT VALID ); --insert values into courses table INSERT INTO "courses" ("courseName") VALUES ('Web Development'); INSERT INTO "courses"("courseName") VALUES('Java Development'); -- insert 2 records into the courses table INSERT INTO "courses"("courseName") VALUES('Python Development'),('Ruby Development'); --insert another record into the courses table INSERT INTO "courses"("courseName") VALUES('C++ development'); --select all the records from table select * from "courses"; --select courseName column from courses table select "courseName" from "courses"; --select all the records from students table select * from "students"; -- Get all the courses SELECT "courseId", "courseName" FROM "courses"; -- Get all the students SELECT "studentId", "courseId", "studentName", "studentEmail", "studentPhone" FROM "students"; --insert values into students table INSERT INTO "students" ("courseId", "studentName", "studentEmail", "studentPhone") VALUES (1, 'John Doe', 'john@doe.com', 2716272); --insert another record into students table INSERT INTO "students"("courseId","studentName","studentEmail","studentPhone") VALUES(2, 'John Doe2','john@doe2.com',2716273); --insert 2 records into students table INSERT INTO "students" ("courseId","studentName", "studentEmail","studentPhone") VALUES (3,'John Doe3', 'john@doe3.com',2716274), (4,'John Doe4', 'john@doe4.com',2716275); -- insert another record into students table INSERT INTO "students"("courseId","studentName","studentEmail","studentPhone") VALUES(5, 'John Doe5','john@doe5.com',2716276); select * from "courses"; select * from "students"; delete from "students"; --get the maximum value of the serial column SELECT MAX("studentId") FROM "students"; -- this can reset the value of serial column in the table --SETVAL('sequence_name', new_value, is_called) SELECT SETVAL(pg_get_serial_sequence('students','studentId'),100,false); -- Get all the students who have a courseId = 2 SELECT * FROM "students" WHERE "courseId" = 2; --get all the student who have studentId=3 SELECT * FROM "students" WHERE "studentId"=3; SELECT MAX("studentId") from "students"; -- Get all the students whose studentId is greater than 1 but less than 5 SELECT * FROM "students" WHERE "studentId" > 1 AND "studentId" < 5; -- Get all the students who do not have data stored for studentPhone SELECT * FROM "students" WHERE "studentPhone" IS NULL; -- Get all the students whose studentName starts with Jo no matter what other letters might follow the Jo SELECT * FROM "students" WHERE "studentName" LIKE 'Jo%'; -- Get all the students whose courseId is present in the list (1, 5) SELECT * FROM "students" WHERE "courseId" IN ( 1, 5 ); -- Get all the students whose courseIds are between 1 AND 5 SELECT * FROM "students" WHERE "courseId" BETWEEN 1 AND 5; --Get all the students whose courseIds are greater than 1 and less than 5 SELECT * from "students" where "courseId">1 AND "courseId"<5; -- Get all the students who have a courseId that is either 1 or 2  SELECT * FROM "students" WHERE "courseId" = 1 OR "courseId" = 2; -- Get all the students who have a courseId = 1 and a missing studentPhone SELECT * FROM "students" WHERE "courseId" = 1 AND "studentPhone" IS NULL; -- Get all the students who have a courseId that is either 1 or 2  SELECT * FROM "students" WHERE "courseId" = 1 OR "courseId" = 2; --Update name of the student that has studentId = 1 to 'Alex'  UPDATE "students" SET "studentName" = 'Alex' WHERE "studentId" = 1; -- Update studentPhone to 18273124 where studentId = 1 and studentName = 'Alex'  UPDATE "students" SET "studentPhone" = 18273124 WHERE "studentId" = 1 AND "studentName" = 'Alex'; -- Update studentPhone to 0 where studentId greater-than 1 and less-than 5 UPDATE "students" SET "studentPhone" = 0 WHERE "studentId" > 1 AND "studentId" < 5; -- Delete a student whose studentId = 1 DELETE FROM "students" WHERE "studentId" = 1; select * from "students"; -- Delete all students whose studentPhone field is empty DELETE FROM "students" WHERE "studentPhone" IS NULL; DELETE FROM "students"; DROP "students"; DELETE FROM "courses"; DROP "courses";

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
icon
Related questions
Question

How to fix this error in pgadmin 4

=====================================

ERROR: syntax error at or near ""students"" LINE 121: DROP "students"; ^ SQL state: 42601 Character: 4630

==================================================================================

 

CREATE TABLE "courses"(
   "courseId" SERIAL,
   "courseName" VARCHAR(120) NOT NULL,
    CONSTRAINT "courses_pk" PRIMARY KEY ("courseId")
);

CREATE TABLE "students"(
   "studentId" SERIAL,
   "courseId" INT NOT NULL,
   "studentName" VARCHAR(120) NOT NULL,
   "studentEmail" VARCHAR(120) UNIQUE NOT NULL,
   "studentPhone" INT NOT NULL,
    CONSTRAINT "students_pk" PRIMARY KEY ("studentId"),
    CONSTRAINT "courses_students_fk" FOREIGN KEY("courseId")
      REFERENCES "courses"("courseId")
      ON UPDATE NO ACTION
      ON DELETE NO ACTION
      NOT VALID
);
--insert values into courses table
INSERT INTO "courses" ("courseName") VALUES ('Web Development');

INSERT INTO "courses"("courseName") VALUES('Java Development');
-- insert 2 records into the courses table
INSERT INTO "courses"("courseName") VALUES('Python Development'),('Ruby Development');
--insert another record into the courses table
INSERT INTO "courses"("courseName") VALUES('C++ development');

--select all the records from table
select * from "courses";
--select courseName column from courses table
select "courseName" from "courses";

--select all the records from students table
select * from "students";

-- Get all the courses
SELECT "courseId", "courseName" FROM "courses";

-- Get all the students
SELECT "studentId", "courseId", "studentName", "studentEmail", "studentPhone" FROM "students";

--insert values into students table
INSERT INTO "students" ("courseId", "studentName", "studentEmail", "studentPhone")
VALUES (1, 'John Doe', 'john@doe.com', 2716272);

--insert another record into students table
INSERT INTO "students"("courseId","studentName","studentEmail","studentPhone")
VALUES(2, 'John Doe2','john@doe2.com',2716273);

--insert 2 records into students table
INSERT INTO "students" ("courseId","studentName", "studentEmail","studentPhone")
VALUES (3,'John Doe3', 'john@doe3.com',2716274),
(4,'John Doe4', 'john@doe4.com',2716275);
-- insert another record into students table
INSERT INTO "students"("courseId","studentName","studentEmail","studentPhone")
VALUES(5, 'John Doe5','john@doe5.com',2716276);


select * from "courses";
select * from "students";

delete from "students";

--get the maximum value of the serial column
SELECT MAX("studentId") FROM "students";
-- this can reset the value of serial column in the table
--SETVAL('sequence_name', new_value, is_called)
SELECT SETVAL(pg_get_serial_sequence('students','studentId'),100,false);

-- Get all the students who have a courseId = 2
SELECT * FROM "students" WHERE "courseId" = 2;

--get all the student who have studentId=3
SELECT * FROM "students" WHERE "studentId"=3;
SELECT MAX("studentId") from "students";

-- Get all the students whose studentId is greater than 1 but less than 5
SELECT * FROM "students" WHERE "studentId" > 1 AND "studentId" < 5;

-- Get all the students who do not have data stored for studentPhone
SELECT * FROM "students" WHERE "studentPhone" IS NULL;

-- Get all the students whose studentName starts with Jo no matter what other letters might follow the Jo
SELECT * FROM "students" WHERE "studentName" LIKE 'Jo%';

-- Get all the students whose courseId is present in the list (1, 5)
SELECT * FROM "students" WHERE "courseId" IN ( 1, 5 );

-- Get all the students whose courseIds are between 1 AND 5
SELECT * FROM "students" WHERE "courseId" BETWEEN 1 AND 5;
--Get all the students whose courseIds are greater than 1 and less than 5
SELECT * from "students" where "courseId">1 AND "courseId"<5;

-- Get all the students who have a courseId that is either 1 or 2 
SELECT * FROM "students" WHERE "courseId" = 1 OR "courseId" = 2;

-- Get all the students who have a courseId = 1 and a missing studentPhone
SELECT * FROM "students" WHERE "courseId" = 1 AND "studentPhone" IS NULL;

-- Get all the students who have a courseId that is either 1 or 2 
SELECT * FROM "students" WHERE "courseId" = 1 OR "courseId" = 2;

--Update name of the student that has studentId = 1 to 'Alex' 
UPDATE "students" SET "studentName" = 'Alex' WHERE "studentId" = 1;

-- Update studentPhone to 18273124 where studentId = 1 and studentName = 'Alex' 
UPDATE "students" SET "studentPhone" = 18273124 WHERE "studentId" = 1 AND "studentName" = 'Alex';

-- Update studentPhone to 0 where studentId greater-than 1 and less-than 5
UPDATE "students" SET "studentPhone" = 0 WHERE "studentId" > 1 AND "studentId" < 5;

-- Delete a student whose studentId = 1
DELETE FROM "students" WHERE "studentId" = 1;
select * from "students";

-- Delete all students whose studentPhone field is empty
DELETE FROM "students" WHERE "studentPhone" IS NULL;

DELETE FROM "students";
DROP "students";

DELETE FROM "courses";
DROP "courses";

Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Single Table
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Database System Concepts
Database System Concepts
Computer Science
ISBN:
9780078022159
Author:
Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:
McGraw-Hill Education
Starting Out with Python (4th Edition)
Starting Out with Python (4th Edition)
Computer Science
ISBN:
9780134444321
Author:
Tony Gaddis
Publisher:
PEARSON
Digital Fundamentals (11th Edition)
Digital Fundamentals (11th Edition)
Computer Science
ISBN:
9780132737968
Author:
Thomas L. Floyd
Publisher:
PEARSON
C How to Program (8th Edition)
C How to Program (8th Edition)
Computer Science
ISBN:
9780133976892
Author:
Paul J. Deitel, Harvey Deitel
Publisher:
PEARSON
Database Systems: Design, Implementation, & Manag…
Database Systems: Design, Implementation, & Manag…
Computer Science
ISBN:
9781337627900
Author:
Carlos Coronel, Steven Morris
Publisher:
Cengage Learning
Programmable Logic Controllers
Programmable Logic Controllers
Computer Science
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education